以30分钟（最近的半小时）递增： [英] Round up in 30 min (nearest half-hour) increments:

问题描述

以30为增量舍入整数的最有效方式（在Java中）是什么。我的输出将是一个整数：

What is the most efficient way (in Java) to round an integer in 30 increments. My output will be an Integer:

这是我的代码，它以整数形式返回分钟。

Here is my code that returns minutes in integer.

long different = endTime.getTime() - startTime.getTime();
int idiff = TimeUnit.MILLISECONDS.toMinutes(different) - TimeUnit.HOURS.toMinutes(TimeUnit.MILLISECONDS.toHours(different));

现在我要整理这个整数。例如：

Now I want to round up this integer. For example:

任意数字< = 30 =向上舍入到30：

Any number <= 30 = round up to 30:

31至60之间的任何数字=向上舍入至60

Any number between 31 to 60 = round up to 60

61至90之间的任何数字=向上舍入至90

Any number between 61 to 90 = round up to 90

91到120之间的任何数字=最多120个

Any number between 91 to 120 = round up to 120

121到150之间的任何数字=最多150个

Any number between 121 to 150 = round up to 150

推荐答案

加一个比你想要的组少一个，然后除以多个..所以30个做

Add one less than the group you want, then divide and multiple.. so for 30 do

((value + 29) / 30) * 30

这假设您希望0保持0,30保持30 ...

This assumes you want 0 to stay at 0, 30 to stay at 30...

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