是否有类似于Java的字符串'charAt（）'方法在C？ [英] is there anything similar to Java's string 'charAt()' Method in C?

问题描述

我正在尝试将一段代码从Java转换为C并且我被困在这里，试图在每个位置获得一个角色。

I'm trying to convert a piece of code from Java to C and I got stuck here, trying to get a character at each position.

char ch;

line += ' ';
    while (pos < line.length()) 
    {
      ch = line.charAt(pos);  
...

在C中有任何类似的转换行 ch = line.charAt（pos）从java到C？

is there anything similar in C to convert the line ch = line.charAt(pos) from java to C?

推荐答案

在C中，给出字符数组中的char的最简单方法（IE为字符串）

in C, the easiest way to get a char from an array of character (I.E. a string)

给出已发布代码中的变量，

given the variables in your posted code,

char ch;

line += ' ';
while (pos < line.length()) 
{
    ch = line.charAt(pos);  
...

1. 假设字符串终止于一个NUL字节（'\0'）


2. 假设 line [] 数组中有另一个字符的空间

1. assuming that the string is terminated with a NUL byte ('\0')
2. assuming there is room in the line[] array for another character

将成为：

#include <string.h>
strcat( line, " ");
size_t maxPos = strlen( line );
for( pos = 0; pos < maxPos; pos++ )
{
    ch = line[pos];
....

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