字符类减法 [英] Character class subtraction

问题描述

我正在使用特定模式尝试获得没有标点符号的句子。
我有这个：

I'm using a specific pattern in attempt to get a sentence without the punctuation. I have this:

 p = Pattern.compile("[\\p{Punct}\\s]+");
 String[] all = p.split("int a = 4;");

我得到数组

all = {int, a, 4};

这很棒，但我希望我的模式也保持[]（如果存在）。例如：

That is great but I want my pattern to also keep "[]" if it exists. for example:

String[] all = p.split("int[] a = 4;");

并获得

all = {int,[], a, 4};

这是我希望模式添加[]的唯一改变。
有没有办法做到这一点？

That is the only change thing I want the pattern to add the "[]" nothing else. Any way to do that?

推荐答案

试试这个：

Pattern p = Pattern.compile("[[\\p{Punct}&&[^\\[\\]]]\\s]+");

[和] 字符被视为标点字符。在拆分字符串时，此正则表达式将排除它们。

The [ and ] characters are considered as punctuation characters. This regex will exclude them when splitting the string.

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