[e-mail]& amp; b = 52我想从这个邮件ID中删除& amp; b = 52哪个字符串函数用于此 [英] [e-mail]&b=52 I want to remove &b=52 from this mail id which String function is used for this

问题描述

请从以下字符串中删除& amp; b = 52 的代码：

Please give me the code for removing the &b=52 from strings such as these:

• [e-mail]& b = 52


• [e-mail]& b = 52


• aaaa @ gmail.com& b = 52

推荐答案

这个怎么样？

String s1 = "[e-mail]&b=52";
String s2 = s1.substring(0, 13);

警告：可能无法在所有情况下都有效。我可以改进它如果您提供有关您的问题的更多信息。

Warning: Might not work in all situations. I can possibly improve it if you give more information about your problem.

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