我可以阻止实现接口吗？ [英] Can I prevent an interface from being implemented?

问题描述

我有以下情况：

public interface A {
    void doSomethingCool();
}

public interface B extends A {
    void doSomethingVeryBCool();
}
public interface C extends A {
    void doSomethingVeryCCool();
}

在我的应用程序中，我只能使用实现B或C的类。但是有部分代码，我想使用a.doSomethingCool（），因为我不知道（也不关心）使用哪种实现。

In my application I can only use classes implementing B or C. But there are parts of the code, where I want to use "a.doSomethingCool()", because I don't know (and don't care) which implementation is used.

我可以强制执行，只有B和C的实现吗？
或者阻止接口A被实现？

Can I enforce, that there are only implementations of B and C? Or prevent the interface A from being implemented?

推荐答案

你不能直接强制执行没有实现的接口，不过你可以使接口包本地：

You cannot directly enforce the interface not being implemented, however you can make the interface package-local:

interface A {...} //no public

这样，包外的类无法看到界面。

This way classes outside that package cannot see the interface.

编辑：然而，这确实意味着你不能做类似的事情

however, this does mean that you cannot do something like

A a = getA();

包裹外的

因为A无法解析。

outside the package because A cannot be resolved.

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