在java中实现deque的问题 [英] Problems with implementing a deque in java

查看:84
本文介绍了在java中实现deque的问题的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

抱歉,继续我在这里提出的问题:这里我正在尝试运行此方法从双面队列(deque)中删除一般值(EltType),但我不断收到错误,我调用insertFirst两次,并将值3插入数组两次,然后,当我运行removeFirst,它将打印出3一次,然后Null。有人可以帮我吗?

  class ArrayBasedDeque< EltType> {

private final int CAPACITY = 10;
私人产能;
private int end;
private EltType deque [];

public ArrayBasedDeque(){
this.capacity = CAPACITY;
deque =(EltType [])(new Object [capacity]);
}


public EltType removeFirst(){
EltType [] tempArray;
EltType返回= deque [0];
tempArray =(EltType [])new Object [capacity];
for(int i = 1; i< capacity; i ++){
tempArray [i-1] = deque [i];
}
deque = tempArray;返回
退货;
}


public boolean isEmpty(){
return end == 0;
}

public void insertFirst(EltType first){
if(!isEmpty()){
EltType [] tempArray;
tempArray =(EltType [])new Object [capacity + 1];
for(int i = 0; i< deque.length; i ++){
tempArray [i + 1] = deque [i];
}
deque = tempArray;
}
deque [0] =第一个;
}

}

谢谢:)

解决方案

明显的问题是 end 永远不会改变。 isEmpty()将始终返回 true 。现在让我们看看你的 insertFirst()方法。

  public void insertFirst (EltType first){
if(!isEmpty()){
EltType [] tempArray;
tempArray =(EltType [])new Object [capacity + 1];
for(int i = 0; i< deque.length; i ++){
tempArray [i + 1] = deque [i];
}

deque = tempArray;
}
deque [0] =第一个;
}

知道 isEmpty()总是返回 true 无论如何,这段代码有什么问题?


sorry, just following on from the question I had here : here I am trying to run this method to remove a generic value (EltType) from a double sided queue(deque), but I keep getting an error in that, I call insertFirst twice, and insert the value "3" into the array twice, then, when I run removeFirst, it will print out "3" once, and then "Null" thereafter. Would anyone be able to help me out please ?

class ArrayBasedDeque<EltType> {

  private final int CAPACITY = 10;
  private int capacity;
  private int end;
  private EltType deque[];  

  public ArrayBasedDeque() {
    this.capacity = CAPACITY;
    deque = (EltType[]) (new Object[capacity]);  
  } 


 public EltType removeFirst() {
    EltType[] tempArray;
    EltType returned = deque[0];
    tempArray = (EltType[]) new Object[capacity];
      for (int i=1;i<capacity;i++) {
        tempArray[i-1] = deque[i]; 
      }
      deque = tempArray;
    return returned;
  }


  public boolean isEmpty() {
    return end == 0;
  }

  public void insertFirst(EltType first) {
    if(!isEmpty()) {
    EltType[] tempArray;
    tempArray = (EltType[]) new Object[capacity+1];
    for (int i=0;i<deque.length;i++) {
      tempArray[i+1] = deque[i]; 
    }
    deque = tempArray; 
    }
   deque[0] = first;
  }

}

Thank you :)

解决方案

The big glaring issue is that end never changes. isEmpty() will always return true. Now let's look at your insertFirst() method.

public void insertFirst(EltType first) {
    if(!isEmpty()) {
        EltType[] tempArray;
        tempArray = (EltType[]) new Object[capacity+1];
        for (int i=0;i<deque.length;i++) {
            tempArray[i+1] = deque[i]; 
        }

        deque = tempArray; 
    } 
    deque[0] = first;
}

Knowing that isEmpty() always returns true no matter what, what is the problem with this piece of code?

这篇关于在java中实现deque的问题的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆