寻找毕达哥拉斯三胞胎的代码 [英] Code for finding pythagorean triplets

问题描述

我目前正在尝试这个问题：

I am currently attempting this question :

毕达哥拉斯三元组是一组三个自然数a，b和c，其中
a ² + b ² = c ² 。

A Pythagorean triplet is a set of three natural numbers, a, b and c, for which a² + b² = c².

例如，3 ² + 4 ² = 9 + 16 = 25 = 5 ² 。

For example, 3² + 4² = 9 + 16 = 25 = 5².

恰好有一个毕达哥拉斯三元组，其中a + b + c = 1000.
查找产品abc。

There exists exactly one Pythagorean triplet for which a + b + c = 1000. Find the product abc.

我的代码如下，我认为它应该是正确的，但该网站告诉我我的答案是错的？有人可以帮我看看我的逻辑中的缺陷吗？

My code is as follows, I think it should be correct, but the site is telling me my answer is wrong? Can someone help me see the flaws in my logic please?

public class Pythagoras {
    public static void main(String[] args) {
            int sum = 1000;
            int a;
            int product=0;
            for (a = 1; a <= sum/3; a++)
            {
                int b;
                for (b = a + 1; b <= sum/2; b++)
                {
                    int c = sum - a - b;
                    if ( c > 0 && (a*a + b*b == c*c) )
                       System.out.printf("a=%d, b=%d, c=%d\n",a,b,c);
                        product = a * b * c;
                }
            }
            System.out.println(product);
        }
    }

推荐答案

我以为你错过了一套大括号。缩进使我相信两个最内层的陈述在一起，但你需要花括号才能正确。

I think you're missing a set of braces. The indentation leads me to believe the two innermost statements go together but you need curly braces for that to be correct.

if ( c > 0 && (a*a + b*b == c*c) )
{
    System.out.printf("a=%d, b=%d, c=%d\n",a,b,c);
    product = a * b * c;
}

没有大括号产品将始终包含最后值 a ， b 的产品，以及 C 。 （333 * 500 * 167 == 27805500）。

Without the braces product will always contain the product of the last values of a, b, and c. (333 * 500 * 167 == 27805500).

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