找到一个真正强大的数字 [英] Finding really big power of a number

问题描述

我正在为学生创建一个小游戏，在一个地方，它必须显示2 ^7830457 +1的价值

I am creating a small game for students, and in a place, it has to display the value of 2^7830457+1

如果数字不是那么大，我可以调用BigInteger的pow（）方法。由于数量很大，这种方法毫无用处。我怎样才能找到这种数字的巨大力量？请帮忙！

I can call BigInteger's pow() method if the number is not this much big. Since the number is very big, that method is useless. How can I find the HUGE power of this kind of numbers? Please help!

推荐答案

我不知道你为什么认为 BigInteger 不能达到这个目的：

I don't know why you think BigInteger isn't up to this:

import java.math.BigInteger;

public class Test {
    public static void main(String[] args) throws Exception {
        BigInteger big = BigInteger.valueOf(2)
            .pow(7830457)
            .add(BigInteger.ONE);
        System.out.println(big);
    }
}

这需要一点时间（特别是字符串转换时间为结束），但这是完全合理的。

It takes a little while (particularly the string conversion at the end), but it's perfectly reasonable.

正如彼得所说，转移 ONE 左7830457更加整洁，记住您。我认为它不太清楚 - 当然它在字符串转换部分没有帮助。

As Peter noted, shifting ONE left 7830457 is much neater, mind you. I'd argue it's a bit less clear - and of course it doesn't help in the string conversion part.

编辑：几乎所有的时间花在了字符串转换。它最后在我的盒子上完成了。我再也看不到它的开始了，但它以......结尾。

Almost all of the time is spent in the string conversion. It finished in the end on my box though. I can't see the start of it any more, but it ends with...

08570502260645006898157834607641626568029302766491883299164453304032280181734737
79366998940913082443120328458954436211937775477966920836932628607888755839700303
873

这篇关于找到一个真正强大的数字的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！