OR比较的Java顺序 [英] Java order of OR comparison

问题描述

当参数为null时，以下代码片段会抛出NPE吗？

does the following snippet throw NPE when argument is null?

public void doSomething(String string) {
    if (string.trim().equals("") || string==null) {
    [...]
    }
}

我在别人的代码中找到了这个（其他人应该比我更有经验）。由于我一直面临着这段代码的困难，我想问一下比较是否应该反转，或者Java编译器是否足够聪明以交换操作数。我没有直接控制这个代码，也没有因为许多catch块而抛出NPE。

I've found this in someone else's code (someone else who should be more experienced than me). Since I've been facing difficulties with this code, I want to ask if the comparison should be inverted or the Java compiler is someway smart enough to swap the operands. I don't have direct control over this code, nor this throws me NPE because of many catch blocks.

谢谢

推荐答案

是的。当 string null NullPointerException >。建议将其更改为以下内容：

Yes. That snippet of code will throw a NullPointerException when string is null. Changing it to the following is advisable:

public void doSomething(String string) {
    if (string==null || string.trim().equals("")) {
        // ...
    }
}

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