Java String特殊字符替换 [英] Java String Special character replacement
本文介绍了Java String特殊字符替换的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我的字符串包含字母数字和特殊字符。
我需要用一些字符串替换每个特殊字符。
I have string which contains alpahanumeric and special character. I need to replace each and every special char with some string.
例如,
输入字符串=ja * va st& ri%n @&
预期o / p =jaasteriskvaspacestandripercentagenatand
Input string = "ja*va st&ri%n@&" Expected o/p = "jaasteriskvaspacestandripercentagenatand"
- =asterisk
& =和
%=百分比
@ =at
谢谢,
推荐答案
除非你非常渴望表现,否则我会采用一种非常简单的方法:
Unless you're absolutely desperate for performance, I'd use a very simple approach:
String result = input.replace("*", "asterisk")
.replace("%", "percentage")
.replace("@", "at"); // Add more to taste :)
(请注意,替换
和 replaceAll
- 后者采用正则表达式。很容易得到错误的并看到截然不同的效果!)
(Note that there's a big difference between replace
and replaceAll
- the latter takes a regular expression. It's easy to get the wrong one and see radically different effects!)
另一种选择是:
public static String replaceSpecial(String input)
{
// Output will be at least as long as input
StringBuilder builder = new StringBuilder(input.length());
for (int i = 0; i < input.length(); i++)
{
char c = input.charAt(i);
switch (c)
{
case '*': builder.append("asterisk"); break;
case '%': builder.append("percentage"); break;
case '@': builder.append("at"); break;
default: builder.append(c); break;
}
}
return builder.toString();
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