Spring MVC中的多响应http状态 [英] Multiple response http status in Spring MVC

问题描述

拥有以下代码：

@RequestMapping(value =  "/system/login", method = RequestMethod.GET)
public void login(@RequestBody Login login) {
    if(login.username == "test" && login.password == "test") {
         //return HTTP 200
    }
    else {
         //return HTTP 400
    }
}

我想根据我的逻辑返回两种不同的HTTP状态。实现这一目标的最佳方法是什么？

I would like to return two different HTTP statuses based on my logic. What is the best way to achieve this?

推荐答案

有人在SO建议的一种方法是抛出不同的例外情况由不同的异常处理程序：

One approach which someone suggested at SO is to throw different exceptions which will be catch by different exception handlers:

@RequestMapping(value =  "/system/login", method = RequestMethod.GET)
public void login(@RequestBody Login login) {
    if(login.username == "test" && login.password == "test") {
         throw new AllRightException();
    }
    else {
         throw new AccessDeniedException();
    }
}

@ExceptionHandler(AllRightException.class)
@ResponseStatus(HttpStatus.OK)
public void whenAllRight() {

}

@ExceptionHandler(AccessDeniedException.class)
@ResponseStatus(HttpStatus.BAD_REQUEST)
public void whenAccessDenied() {

}

参见：

'LI> @ExceptionHandler

• @ ResponseStatus

• @ExceptionHandler
• @ResponseStatus

BTW，您的示例代码包含错误： login。密码==测试你应该使用 equals（）那里：）

BTW, your example code contains error: login.password == "test" you should use equals() there :)

已更新：我发现了另一种更好的方法，因为它不使用例外：

Updated: I found another approach which even better because it doesn't use exceptions:

@RequestMapping(value =  "/system/login", method = RequestMethod.GET)
public ResponseEntity<String> login(@RequestBody Login login) {
    if(login.username == "test" && login.password == "test") {
         return new ResponseEntity<String>("OK" HttpStatus.OK);
    }

    return new ResponseEntity<String>("ERROR", HttpStatus.BAD_REQUEST);
}

参见ResponseEntity API

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