用'，'拆分句子并删除周围的空格 [英] Split the sentences by ',' and remove surrounding spaces

问题描述

我有这段代码：

var r = /(?:^\s*([^\s]*)\s*)(?:,\s*([^\s]*)\s*){0,}$/
var s = "   a   ,  b  , c "
var m = s.match(r)
m => ["   a   ,  b  , c ", "a", "c"]

看起来像整个字符串已匹配，但哪里有b消失了？我希望得到：

Looks like the whole string has been matched, but where has "b" gone? I would rather expect to get:

["   a   ,  b  , c ", "a", "b", "c"]

这样我就可以 m.shift（）结果如 s.split（'，'），但也删除了空格。

so that I can do m.shift() with a result like s.split(',') but also with whitespaces removed.

我是否在regexp中有错误或者我误解了 String.prototype.match ？

Do I have a mistake in the regexp or do I misunderstand String.prototype.match?

推荐答案

所以最后我去了 /（？= \S）[^，] +？（？= \ * *（，| $））/ g ，它提供了我所需要的：所有句子用'，'分隔，没有周围的空格。

so finally i went with /(?=\S)[^,]+?(?=\s*(,|$))/g, which provides exactly what i need: all sentences split by ',' without surrounding spaces.

'       a,    OMG     abc b a b, d o WTF        foo     '.
  match( /(?=\S)[^,]+?(?=\s*(,|$))/g )
=> ["a", "OMG     abc b a b", "d o WTF        foo"]

非常感谢！

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