计算字符串中字符的出现次数 [英] Counting occurence of character in a string

问题描述

是否有标准的库函数可以计算字符串中字符的数量？


问候，


Michael

解决方案

Michael McGarry写道：

你好，

是否有标准的库函数来计算字符串中字符的出现次数？

No.


-

pete

pete写道：

Michael McGarry写道：

是否有标准库函数计算
字符串中字符的出现？

否。

如果是，它可能会被实现沿着这条线...


size_t strccnt（const char * s，int c）

{

const unsigned cha r * us =（const unsigned char *）s;

const unsigned char uc = c;

size_t n = 0;

if（ ！uc）返回1;

while（* us）if（* us ++ == uc）n ++;

return n;

}


-

彼得

2005年11月21日20:30:46 -0800，Michael McGarry

< mi ************* @ gmail.com>写道：

是否有标准的库函数来计算字符串中字符的出现次数？

否

<<删除电子邮件的del>>

Hi,

Is there a standard library function that counts the number of
occurences of a character in a string?

Regards,

Michael

解决方案

Michael McGarry wrote:

Hi,

Is there a standard library function that counts the number of
occurences of a character in a string?

No.

--
pete

pete wrote:

Michael McGarry wrote:

Hi,

Is there a standard library function that counts the number of
occurences of a character in a string?

No.

If it were, it would probably be implemented along the lines of...

size_t strccnt(const char *s, int c)
{
const unsigned char *us = (const unsigned char *) s;
const unsigned char uc = c;
size_t n = 0;
if (!uc) return 1;
while (*us) if (*us++ == uc) n++;
return n;
}

--
Peter

On 21 Nov 2005 20:30:46 -0800, "Michael McGarry"
<mi*************@gmail.com> wrote:

Hi,

Is there a standard library function that counts the number of
occurences of a character in a string?

No
<<Remove the del for email>>

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