计算字符串中数字出现的次数 [英] Count number of occurrences of a digit within a string

问题描述

因此，我试图计算数组中每个数字的出现次数.

So I'm trying to count the number of occurrences of each digit within an array.

到目前为止，我的代码如下:

My code I've got so far looks like the following:

#include <stdio.h>
#include <string.h>

int main()
{
  int numbers [10]= {1, 4, 5, 5, 5, 6, 6, 3, 2, 1};
  int count = 0;

  for(int i = 0; i < 10; i++)
  {
    for (int j = 0; j < 10; j++)
    {
      if (numbers[i] == numbers[j])
      {
        count++;
      }
    }
    printf("Number %d has occured %d many times \n", numbers[i], count);
    count = 0;

  }
} 

只有我得到的输出如下:

Only the output I get is the following:

Number: 1       Occurence: 2
Number: 4       Occurence: 1
Number: 5       Occurence: 3
Number: 5       Occurence: 3
Number: 5       Occurence: 3
Number: 6       Occurence: 2
Number: 6       Occurence: 2
Number: 3       Occurence: 1
Number: 2       Occurence: 1
Number: 1       Occurence: 2 

我只想计算每个数字的出现，似乎是在计算重复项.

I only want to count the occurrence of EACH digit, it seems to be counting duplicates.

如何纠正此代码?有人可以指出我正确的方向.

How can I correct this code? Can someone point me in the right direction.

非常感谢

阿隆索

推荐答案

请考虑以下修改的代码:

Consider this modified code:

#include <stdio.h>
#include <string.h>

int main()
{
  int numbers [10]= {1, 4, 5, 5, 5, 6, 6, 3, 2, 1};
  int count = 0;

  for(int i = 0; i < 10; i++) { //i = current digit
    for (int j = 0; j < 10; j++) { //j = index in array
      if (i == numbers[j]) {
        count++;
      }
    }
    printf("Number %d has occured %d times \n", i, count);
    count = 0;
  }
}

输出:

Number 0 has occured 0 times 
Number 1 has occured 2 times 
Number 2 has occured 1 times 
Number 3 has occured 1 times 
Number 4 has occured 1 times 
Number 5 has occured 3 times 
Number 6 has occured 2 times 
Number 7 has occured 0 times 
Number 8 has occured 0 times 
Number 9 has occured 0 times 

您正在计算数组中每个数字出现的频率(包括数组中重复的数字).

You were counting how often each digit occuring in the array (including duplicate digits in the array) occured.

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