如何计算字符串中字符串的出现次数？ [英] How would I count occurrences of a string within a string?

问题描述

我使用以下代码查找字符串中的匹配字符串。

I used the following code to find the matches string within a string.

int x = Regex.Matches("I am good bad good bad bad boy", "bad").Count;

这里输出x = 3。



现在关注我的问题。

Here output x=3.

Now follow my problem.

int x = Regex.Matches("I have a Voucher in AllVoucher", "Voucher").Count;

这里输出x = 2！



此程序还会计算AllVoucher的优惠券。但是我想要计算凭证可以从任何东西开始的地方（如-Voucher，.Vouchar）除了字母。喜欢

Here output x=2!

This program also count Voucher from AllVoucher. But I want to count Voucher where Voucher can start with anything(like -Voucher, .Vouchar) except letter. Like

int x = Regex.Matches("I have a -Voucher in /Voucher", "Voucher").Count;

这里预期输出x = 2;



但是对于预期的以下行是x = 1;

here expected output x=2;

But for the following line expected out is x=1;

int x = Regex.Matches("I have a Voucher in AllVoucher", "Voucher").Count;

这里输出x = 2！







请使用C＃.NET给我一个解决方案。如何计算匹配字符串，其中匹配字符串可以从除字母之外的任何内容开始。

Here output x=2!



Please give me a solution using C#.NET. How can I count matches string where matches string can start with anything except letter.

推荐答案

int CountWords(string input, string wordToFind)
{
    string pattern = string.Format(@"\b{0}\b", wordToFind);

    return Regex.Matches(input, pattern).Count;
}

您可以这样调用此方法：



例如

You can call this method like this:

e.g.

int count = CountWords("I have a -Voucher in /Voucher", "Voucher")

string source = "I am good bad good bad bad boy";
int count = source.Count(f => f == 'bad');

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