来自'char'tp'char *'的转换无效 [英] Invalid conversion from 'char' tp 'char*'
问题描述
我是C ++的新手，并试图开始制作一个可以随机播放
数组的脚本。有人可以告诉我有什么问题吗？
#include< iostream.h>
#include< string.h>
int main（）{
srand（time（0））;
int array_length;
int count;
int randm;
char temp [30];
cout<< 阵列中有多少项？ " ;;
cin>> array_length;
char items [30] [array_length + 1];
for（count = 0; count< = array_length; count ++）{
if（count！= 0）{
cout<< \\\
What shall item <<计数<< "是？\ n\t" ;;
}
cin.getline（items [count]，30）;
}
count = 0; count< array_length; count ++）{
randm = rand（）％array_length;
strcpy（temp [30] ，项目[30] [count]）;
//错误
strcpy（项目[30] [计数]，项目[30] [randm]）; // ERROR
strcpy（items [30] [randm]，temp [30]）; //错误
}
返回0;
}
有人可以告诉我有什么问题吗？我得到的错误是：
21：错误：无效转换为''char''到''char *''
21：错误：转换无效'' char''to''const char *''
22：错误：无效转换为''char''到''char *''
22：错误：无效转换从''char''到''const char *''
23：错误：从''char''无效转换为''char *''
23：错误：无效转换从''char''到''const char *''
I''m new to C++, and tried to start making a script that will shuffle an
array. Can someone please tell me what''s wrong?
#include <iostream.h>
#include <string.h>
int main () {
srand(time(0));
int array_length;
int count;
int randm;
char temp[30];
cout << "How many items in array? ";
cin >> array_length;
char items [30][array_length + 1];
for (count = 0; count <= array_length; count++) {
if (count != 0) {
cout << "\nWhat shall item " << count << " be?\n\t";
}
cin.getline (items[count], 30);
}
for (count = 0; count < array_length; count++) {
randm = rand() % array_length;
strcpy (temp[30], items[30][count]);
//ERROR
strcpy (items[30][count], items[30][randm]); //ERROR
strcpy (items[30][randm], temp[30]); //ERROR
}
return 0;
}
Can someone please tell me what is wrong? The errors I get are:
21: error: invalid conversion from ''char'' to ''char*''
21: error: invalid conversion from ''char'' to ''const char*''
22: error: invalid conversion from ''char'' to ''char*''
22: error: invalid conversion from ''char'' to ''const char*''
23: error: invalid conversion from ''char'' to ''char*''
23: error: invalid conversion from ''char'' to ''const char*''
推荐答案
Tim Johansson写道：
Tim Johansson wrote:
我是C ++的新手，并试图开始制作一个脚本
^^^^^^
仅供参考，C ++程序不是脚本，它们是' '重新编程。
将改组阵列。有人可以告诉我什么是错的吗？
I''m new to C++, and tried to start making a script ^^^^^^
FYI, C++ programs are not "scripts", they''re programs.
that will shuffle
an array. Can someone please tell me what''s wrong?
< snip>
我不确定出了什么问题（我无法理解）但是这里有点
随机程序：
int main（）
{
//用于保存项目的字符串向量
std :: vector< std :: string>物品;
//获取物品
std :: cout<< 输入项目，或空白以完成： << std :: endl;
for（;;）
{
std :: string item;
std :: getline（std :: cin，item）;
if（item ==""）
break;
items。 push_back（item）;
}
std :: cout<< std :: endl<< 洗牌物品： << std :: endl;
//使用< algorithm>中的random_shuffle算法shuffe序列
std :: random_shuffle（items.begin（），items.end（））;
//将混洗后的向量复制到std :: cout
std :: copy（items.begin（），items.end（），
std :: ostream_iterator< std :: string>（std :: cout，" \ n"））;
}
此外，我建议您阅读免费&合法的用C ++思考布鲁斯的书
Eckel，可在作者的网站上找到， www。 mindview.net 。
- Pete
<snip>
I''m not sure what was wrong (I couldn''t understand it) but here''s a little
shuffle program:
int main()
{
// a vector of strings to hold the items
std::vector<std::string> items;
// get items
std::cout << "Enter items, or blank to finish:" << std::endl;
for(;;)
{
std::string item;
std::getline(std::cin, item);
if(item == "")
break;
items.push_back(item);
}
std::cout << std::endl << "Shuffled items:" << std::endl;
// use the random_shuffle algorith in <algorithm> to shuffe the sequence
std::random_shuffle(items.begin(), items.end());
// copy the shuffled vector to std::cout
std::copy(items.begin(), items.end(),
std::ostream_iterator<std::string>(std::cout, "\n"));
}
Also, I suggest you read the free & legal "Thinking in C++" book by Bruce
Eckel, availible at the author''s website, www.mindview.net.
- Pete
Tim Johansson写道：
Tim Johansson wrote:
I 我是C ++的新手，并试图开始编写脚本
^^^^^^
仅供参考，C ++程序不是脚本，它们是程序。 br />
会洗牌一个阵列。有人可以告诉我什么是错的吗？
I''m new to C++, and tried to start making a script ^^^^^^
FYI, C++ programs are not "scripts", they''re programs.
that will shuffle
an array. Can someone please tell me what''s wrong?
< snip>
我不确定出了什么问题（我无法理解）但是这里有点
随机程序：
int main（）
{
//用于保存项目的字符串向量
std :: vector< std :: string>物品;
//获取物品
std :: cout<< 输入项目，或空白以完成： << std :: endl;
for（;;）
{
std :: string item;
std :: getline（std :: cin，item）;
if（item ==""）
break;
items。 push_back（item）;
}
std :: cout<< std :: endl<< 洗牌物品： << std :: endl;
//使用< algorithm>中的random_shuffle算法shuffe序列
std :: random_shuffle（items.begin（），items.end（））;
//将混洗后的向量复制到std :: cout
std :: copy（items.begin（），items.end（），
std :: ostream_iterator< std :: string>（std :: cout，" \ n"））;
}
此外，我建议您阅读免费&合法的用C ++思考布鲁斯的书
Eckel，可在作者的网站上找到， www。 mindview.net 。
- Pete
<snip>
I''m not sure what was wrong (I couldn''t understand it) but here''s a little
shuffle program:
int main()
{
// a vector of strings to hold the items
std::vector<std::string> items;
// get items
std::cout << "Enter items, or blank to finish:" << std::endl;
for(;;)
{
std::string item;
std::getline(std::cin, item);
if(item == "")
break;
items.push_back(item);
}
std::cout << std::endl << "Shuffled items:" << std::endl;
// use the random_shuffle algorith in <algorithm> to shuffe the sequence
std::random_shuffle(items.begin(), items.end());
// copy the shuffled vector to std::cout
std::copy(items.begin(), items.end(),
std::ostream_iterator<std::string>(std::cout, "\n"));
}
Also, I suggest you read the free & legal "Thinking in C++" book by Bruce
Eckel, availible at the author''s website, www.mindview.net.
- Pete
" Tim Johansson" < SP ** @ gurka.se>在留言中写道
news：c5 ************* @ ID-224346.news.uni-berlin.de ...
"Tim Johansson" <sp**@gurka.se> wrote in message
news:c5*************@ID-224346.news.uni-berlin.de...
我是C ++的新手，并试图开始制作一个可以改组
数组的脚本。有人可以告诉我什么是错的吗？
#include< iostream.h>
#include< string.h>
int main（ ）{/ / srand（time（0））;
int array_length;
int count;
int randm;
char temp [30];
cout << 阵列中有多少项？ " ;;
cin>> array_length;
char items [30] [array_length + 1];
for（count = 0; count< = array_length; count ++）{
if（count！= 0）{
cout<< \\\
What shall item <<计数<< "对于（count = 0; count< array_length）来说，cin.getline（items [count]，30）;
}
是什么？\ n \> ;;
}
; count ++）{
randm = rand（）％array_length;
strcpy（temp [30]，items [30] [count]）;
// ERROR
strcpy（items [30] [count]，items [30] [randm]）; // ERROR
strcpy（items [30] [randm]，temp [30]）;
//错误}
返回0;
}
有人可以告诉我有什么问题吗？我得到的错误是：
21：错误：从''char''无效转换为''char *''
21：错误：从''char''转换为''const char无效*''
22：错误：从''char''无效转换为''char *''
22：错误：无效转换为''char''到''const char *''
23：错误：从''char''无效转换为''char *''
23：错误：无效转换为''char''到''const char *''
I''m new to C++, and tried to start making a script that will shuffle an
array. Can someone please tell me what''s wrong?
#include <iostream.h>
#include <string.h>
int main () {
srand(time(0));
int array_length;
int count;
int randm;
char temp[30];
cout << "How many items in array? ";
cin >> array_length;
char items [30][array_length + 1];
for (count = 0; count <= array_length; count++) {
if (count != 0) {
cout << "\nWhat shall item " << count << " be?\n\t";
}
cin.getline (items[count], 30);
}
for (count = 0; count < array_length; count++) {
randm = rand() % array_length;
strcpy (temp[30], items[30][count]);
//ERROR
strcpy (items[30][count], items[30][randm]); //ERROR
strcpy (items[30][randm], temp[30]); //ERROR }
return 0;
}
Can someone please tell me what is wrong? The errors I get are:
21: error: invalid conversion from ''char'' to ''char*''
21: error: invalid conversion from ''char'' to ''const char*''
22: error: invalid conversion from ''char'' to ''char*''
22: error: invalid conversion from ''char'' to ''const char*''
23: error: invalid conversion from ''char'' to ''char*''
23: error: invalid conversion from ''char'' to ''const char*''
不是我是专家但你似乎试图传递一个单独的段
的数组而不是全部数组，摆脱''[30]''。另外，我不认为你可以通过一个二维数组来strcpy。
Not that I''m a expert but you appear to be trying to pass a single segment
of the array instead of all of the array, get rid of the ''[30]''. Also I
don''t think you can pass a two dimentional array to strcpy.
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