从char *转换为char ** [英] char* to char**

问题描述

我们如何将char*分配给char** ????

例如:

How can we assign char* to char**??

For example:

char ** strArray = (char **)malloc(N*sizeof(char));
char *str ;
std::string st ("Hi there how are you??");
str = new char[st.size()+1];
strcpy(str, st.c_str());

strArray[1] = ??? <-----str (copy str contents to strArray)

问候，

Abhishek Dey

Regards,

Abhishek Dey

推荐答案

您已将strArray定义为char*的数组(即，指向字符串的指针)，但是分配的大小为N *单个字符.我怀疑你的意思是

You have defined strArray as an array of char* (i.e. pointers to character strings) but your allocation is of N * the size of a single character. I suspect what you meant was

char ** strArray = (char **)malloc(N * sizeof(char*));

然后，您可以使用诸如
的分配

Then you could use an assignment such as

strArray[1] = str;  // save the address of this string to strArray

是的....我在那里犯了一个可怕的错误.谢谢帕里尼(Thanx Pallini).

Yes....I made a terrible mistake there. Thanx Pallini.

这篇关于从char *转换为char **的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！