24：21：错误：从'char'无效转换为'char *'[-fpermissive] [英] 24:21: error: invalid conversion from 'char' to 'char*' [-fpermissive]

问题描述

#include <iostream>
#include<cstring>
using namespace std;
int count=0;
void reverseit(char st[100])
{
    char *c,*d,temp;
    for(int i=1;i<=count;i++)
    {
        c=&st[i];       //begining pointer
        d=&st[count];   //last pointer
        temp=*c;
        st[i]=*d;
        st[count]=temp;
        count--;
    }
}
int main() {
    char ch[100];
    cout<<"enter the string to reverse it";
    cin.getline(ch,100);
    cout.write(ch,100);
    count=std::strlen(ch);
    reverseit(ch[100]);
	return 0;
}

无法排序2个错误



我尝试了什么：



无法解决两个错误但很难做到的事情

not able to sort 2 errors

What I have tried:

NOT ABLE TO SOLVE TWO ERRORS TRIED ALOT BUT NOT ABLE TO DO SO

推荐答案

void reverseit(char st[100])

此签名表明， reverseit 接受一个100个字符长的数组，但你用一个字符串调用它...

This signature states, that reverseit accepts a 100 char long array, but you call it with a single char...

reverseit(ch[100]);

你应该改变它：

You should change it like this:

reverseit(ch);

当你解决上述问题时，会出现一个更大的问题，数组从索引0开始......不是1



你的循环

When you fix the above there is a much bigger problem, Arrays start at index 0 ... NOT 1

Your loop

for(int i=1;i<=count;i++)

我可以向你保证i = 1是st [1]不是这一系列的第一个字符de

I can assure you that when i=1 is st[1] is NOT THE FIRST CHARACTER from this line of code

c=&st[i];       //begining pointer

类似地，下一行不是你期望的，当i = 1时将获取＃0，因此你将打印一个空字符串。 />

Similarly this next line will not be what you are expecting and will fetch #0 when i=1 and thus you will print an empty string.

d=&st[count];   //last pointer

您可能想修复这些并记住Arrays从索引0开始蚀刻它在你头脑中： - ）

You might want to fix these and remember Arrays start at index 0 etch it in your head :-)

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