算法实现 [英] algorith implementation
问题描述
template< class OutputIterator，class Size，class T>
void fill_n（OutputIterator first，size n，const T& value）
{
while（n-- 0）* first ++ = value;
}
如果Size必须可转换为整数类型，这不是
实现不包括将枚举值作为第二个
参数传递？枚举值可以转换为整数类型，因此
实现与规范不匹配。
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template <class OutputIterator, class Size, class T>
void fill_n (OutputIterator first, Size n, const T& value)
{
while (n-- 0) *first++ = value;
}
If Size must be convertible to an integral type is this not an
implementation that excludes passing an enum value as the second
parameter? An enum value is convertible to an integral type so the
implementation does not match the specification.
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推荐答案
Fraser Ross写道：
Fraser Ross wrote:
template< class OutputIterator，class Size，class T>
void fill_n（OutputIterator first，size n，const T& value）
{
while（n-- 0）* first ++ = value;
}
如果Size必须可以转换为整数类型，这不是
实现，它排除了将枚举值作为第二个传递
参数？枚举值可以转换为整数类型，因此
实现与规范不匹配。
template <class OutputIterator, class Size, class T>
void fill_n (OutputIterator first, Size n, const T& value)
{
while (n-- 0) *first++ = value;
}
If Size must be convertible to an integral type is this not an
implementation that excludes passing an enum value as the second
parameter? An enum value is convertible to an integral type so the
implementation does not match the specification.
正确。你在哪里找到这个？更好的方法是制作
void fill_n（首先是OutputIterator，大小为n_arg，const T& value）
{
size_t n = n_arg; ...
，可能。
V
-
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Correct. Where did you find this one? A better way would be to make
it
void fill_n (OutputIterator first, Size n_arg, const T& value)
{
size_t n = n_arg; ...
, probably.
V
--
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Victor Bazarov写道：
Victor Bazarov wrote:
正确。你在哪里找到这个？
Correct. Where did you find this one?
我在gcc的STL中发现了同样的问题。确实sgi'的STL文档
定义了尺寸必须是整数类型的要求。
Jens
I found the same issue in gcc''s STL. Indeed sgi''s STL documentation
defines the requirement to be that Size must be an integral type.
Jens
< br>
Jens Theisen写道：
Jens Theisen wrote:
Victor Bazarov写道：
Victor Bazarov wrote:
>正确。你在哪里找到这个？
>Correct. Where did you find this one?
我在gcc的STL中发现了同样的问题。事实上，sgi'的STL文档
定义了Size必须是一个整数类型的要求。
I found the same issue in gcc''s STL. Indeed sgi''s STL documentation
defines the requirement to be that Size must be an integral type.
该标准现已存在（自1997年以来），因此任何C ++
标准库实现都不会使用本地OP暗示变量是
无法使用枚举。
V
-
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The requirement now exists in the Standard (since 1997), so any C++
standard library implementation that doesn''t use a local variable is
not going to work with enums, as the OP hinted.
V
--
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I do not respond to top-posted replies, please don''t ask
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