Retinex算法实现 [英] Retinex algorithm implementation

问题描述

我需要实施单尺度视网膜和多尺度视网膜算法在C＃，

我搜索了一下，但找不到任何有用的练习项目和代码的艺术品。
据我理解正确，我应该：

I need to implement Single Scale retinex and multiscale retinex algorithm in C#,
I searched a bit but couldn't find any useful practice projects and artilces with code
As I understood correctly I should:

1. 将RGB转换为YUV


2. 使用高斯模糊滤镜模糊图像


3. 使用我'（x，y）= 255 * log10（I（x，y）/ G（x，y））+ 127.5
   
   I - 是照明，G - 高斯核，我' - 结果图片


4. Сonvert返回YUV为RGB

1. Convert RGB to YUV
2. Blur the image using Gaussian blur filter
3. Use I'(x, y) = 255*log10( I(x, y)/G(x, y) ) + 127.5
   I - is illumination, G - Gaussian kernel, I' - the result image
4. Сonvert back YUV to RGB

此代码无法正常工作

 public static Image<Bgr, byte> SingleScaleRetinex(this Image<Bgr, byte> img, int gaussianKernelSize, double sigma)
            {
                var radius = gaussianKernelSize / 2;
                var kernelSize = 2 * radius + 1;

                var ycc = img.Convert<Ycc, byte>();

                var sum = 0f;
                var gaussKernel = new float[kernelSize * kernelSize];
                for (int i = -radius, k = 0; i <= radius; i++, k++)
                {
                    for (int j = -radius; j <= radius; j++)
                    {
                        var val = (float)Math.Exp(-(i * i + j * j) / (sigma * sigma));
                        gaussKernel[k] = val;
                        sum += val;
                    }
                }
                for (int i = 0; i < gaussKernel.Length; i++)
                    gaussKernel[i] /= sum;

                var gray = new Image<Gray, byte>(ycc.Size);
                CvInvoke.cvSetImageCOI(ycc, 1);
                CvInvoke.cvCopy(ycc, gray, IntPtr.Zero);

                // Размеры изображения
                var width = img.Width;
                var height = img.Height;

                var bmp = gray.Bitmap;
                var bitmapData = bmp.LockBits(new Rectangle(Point.Empty, gray.Size), ImageLockMode.ReadWrite, PixelFormat.Format8bppIndexed);

                unsafe
                {
                    for (var y = 0; y < height; y++)
                    {
                        var row = (byte*)bitmapData.Scan0 + y * bitmapData.Stride;
                        for (var x = 0; x < width; x++)
                        {
                            var color = row + x;

                            float val = 0;

                            for (int i = -radius, k = 0; i <= radius; i++, k++)
                            {
                                var ii = y + i;
                                if (ii < 0) ii = 0; if (ii >= height) ii = height - 1;

                                var row2 = (byte*)bitmapData.Scan0 + ii * bitmapData.Stride;
                                for (int j = -radius; j <= radius; j++)
                                {
                                    var jj = x + j;
                                    if (jj < 0) jj = 0; if (jj >= width) jj = width - 1;

                                    val += *(row2 + jj) * gaussKernel[k];

                                }
                            }

                            var newColor = 127.5 + 255 * Math.Log(*color / val);
                            if (newColor > 255)
                                newColor = 255;
                            else if (newColor < 0)
                                newColor = 0;
                            *color = (byte)newColor;
                        }
                    }
                }
                bmp.UnlockBits(bitmapData);

                CvInvoke.cvCopy(gray, ycc, IntPtr.Zero);
                CvInvoke.cvSetImageCOI(ycc, 0);

                return ycc.Convert<Bgr, byte>();

            }

推荐答案

看看：
http://www.fer.unizg.hr/ipg/resources/ color_constancy

这些算法是对Retinex算法的修改（速度提升），尽管作者给了他们有趣的名字：）

These algorithms are modifications of the Retinex algorithm (with speed improvement) although the author gave them funny names :)

有一个完整的源代码（C ++，但编写得非常好）。

There is a full source code (C++, but it is written very nicely).

这篇关于Retinex算法实现的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！