试图完成一个输入事件，但输入事件接收器已被释放 [英] Attempted to finish an input event but input event receiver has already been disposed

问题描述

我有我的列表视图自定义适配器。该适配器包含一个TextView和一个图像按钮。我已经实现在点击图像按钮的弹出式菜单。一切工作正常。但选择的选项，从弹出菜单中，显示的logcat一行消息时试图完成一个输入事件，但输入事件接收器已被释放，并没有什么发生。

I have a custom adapter for my listview. The adapter contains a textview and a image button. I have implemented a popup menu on clicking the image button. Everything is working fine. But when selecting the options from popup menu, logcat displaying a single line message "Attempted to finish an input event but input event receiver has already been disposed" and nothing is happening.

public class MyAdapter extends ArrayAdapter<String> {

    public MyAdapter(Context context, int resourceId) {
        super(context, resourceId);
    }

    public MyAdapter(Context context, int resourceId, List<String> string) {
        super(context, resourceId, string);
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        View v = convertView;
        if(v == null) {
            LayoutInflater inflater = LayoutInflater.from(getContext());
            v = inflater.inflate(R.layout.adapter_layout, null);
        }

        String str = getItem(position);

        if(str != null) {
            TextView textView = (TextView)v.findViewById(R.id.editText1);
            textView.setText(str);
            ImageButton button = (ImageButton)v.findViewById(R.id.imageButton1);
            button.setOnClickListener(new Custom_Adapter_Button_Click_Listener(getItemId(position), getContext()));
        }

        return v;
    }
}

onclicklistener接口

onclicklistener interface is

public class Custom_Adapter_Button_Click_Listener implements OnClickListener, OnMenuItemClickListener {

    long position;
    Context context;

    public Custom_Adapter_Button_Click_Listener(long id, Context appcontext) {
        position = id;
        context = appcontext;
    }



    @Override
    public boolean onMenuItemClick(MenuItem item) {
        AdapterContextMenuInfo info = (AdapterContextMenuInfo)item.getMenuInfo();
        int index = info.position;
        Log.d("ItemClicked", "selected index : " + index);
        switch(item.getItemId()) {
        case R.id.option :
            Toast.makeText(context, "Selected index : " + index, Toast.LENGTH_SHORT).show();
            return true;

        default :
            Toast.makeText(context, "Default", Toast.LENGTH_SHORT).show();
            return false;
        }
    }

    @Override
    public void onClick(View v) {
        PopupMenu popup = new PopupMenu(context, v);
        MenuInflater popupInflater = popup.getMenuInflater();
        popupInflater.inflate(R.menu.contextmenu, popup.getMenu());
        popup.show();   

    }

}

我从消息理解的是，有些事情是吃onMenuItemClick之前的事件（）被执行。我的关系运行我的应用程序5款Android 5.0.1。

What I understood from the message is that some thing is eating the event before onMenuItemClick() gets execute. I am running my app on nexus 5 android 5.0.1.

我找到类似的问题的解决方案，从这里。但我没有得到如何使用这种方法来我的问题。

I find a solution for similar kind of problem from here. But I am not getting how to use this approach to my problem.

我试图用上下文菜单，而不是弹出式菜单，但我仍然有同样的消息试图完成一个输入事件，但输入事件接收器已被释放点击右键菜单项后。

I tried using context menu instead of popup menu, but still I had the same message "Attempted to finish an input event but input event receiver has already been disposed" after clicking on the context menu item.

请帮我... !!

推荐答案

我已经打从另一个角度这个问题;试图从菜单中启动的服务。缺省情况下，调试消息是不是太重要。我的解决办法是消除logcat的过滤器，然后我得到了另一个消息，它无法启动的第一个服务到位（我忘了把它放在我的manifest文件）。

I've hit this problem from another angle; trying to launch a service from a menu. By default, the debug message is not too relevant. My solution was to eliminate filters in logcat and then I got another message that it could not launch the service in the first place (I forgot to put it in my manifest file).

在你的情况，你可能需要包装敬酒显示成一个类：

In your case, you may need to wrap the toast display into a class:

public class DisplayToast implements Runnable {
    private final Context mContext;
    private final String mText;

    public DisplayToast(Context mContext, String text) {
        this.mContext = mContext;
        mText = text;
    }

    public void run() {
        Toast.makeText(mContext, mText, Toast.LENGTH_SHORT).show();
    }
}

和通过处理程序对象调用它：

mHandler.post(new DisplayToast(this, "Epic message!"));

，或者甚至更好，使用 Handler.postDelayed（）方法。

心连心，

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