将char [4]（二进制）转换为unsigned long [英] convert a char[4] (binary) to an unsigned long

问题描述

大家好，


我想将char [4]（二进制）转换为unsigned long。我该怎么办？

这个？


谢谢，

Vincent

Hi all,

I want to convert a char[4] (binary) to an unsigned long. How can I do
this?

Thanks,
Vincent

推荐答案

Vincent sade：

Vincent sade:

大家好，

我想将char [4]（二进制）转换为unsigned long 。我该怎么办？

谢谢，
Vincent

Hi all,

I want to convert a char[4] (binary) to an unsigned long. How can I do
this?

Thanks,
Vincent

断言（sizeof（long）== 4 ）;

char b [4] = {0x01,0x02,0x03,0x04};

unsigned long a = 0;

a | = （b [0]<< 24）;

a | =（b [1]<< 16）;

a | =（b [2]< ;< 8）;

a | = b [3];


但如果您在b [3]中有MSB，那么您应该撤销订单。

小心大端和小端。


Tobias

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是非法的。

assert(sizeof(long) == 4);
char b[4] = {0x01,0x02,0x03,0x04};
unsigned long a = 0;
a |= (b[0] << 24);
a |= (b[1] << 16);
a |= (b[2] << 8);
a |= b[3];

But if you have MSB in b[3] then you should reverse the order.
Beware of big endian and little endian.

Tobias
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Vincent写道：

Vincent wrote:

大家好，

我想将char [4]（二进制）转换为unsigned long。我怎么能这样做？

谢谢，
Vincent

Hi all,

I want to convert a char[4] (binary) to an unsigned long. How can I do
this?

Thanks,
Vincent

我认为这不可能不知道

机器的字节顺序。也许有人会纠正我。


如果char [4]来自机器，那么你可能会做一个

reinterpret_cast，但我是几乎是积极的，它不会是便携式的。


//假设这有你的二进制无符号长

extern char ul_bin [4];

unsigned long ul = * reinterpret_cast< unsigned long *>（ul_bin）;


- John Ratliff

I don''t think this is possible without knowing the endian-ness of the
machine. Maybe someone will correct me.

If the char[4] came from the machine, then you could probably do a
reinterpret_cast, but I''m almost positive it won''t be portable.

// assume this has your binary unsigned long
extern char ul_bin[4];
unsigned long ul = *reinterpret_cast<unsigned long *>(ul_bin);

--John Ratliff

该程序必须在MS Windows 2000上运行。字符[4]是一组

字符，从文件中读取。


我希望这将有助于您回答我的问题。

The program will have to work on MS Windows 2000. The char[4] is a set
of characters, read from a file.

I hope this will help you answering my question.

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