用括号分割单词 [英] splitting words with brackets
问题描述
我有一些要拆分的字符串。它们是主要的词，但有些词语
在一对括号内，应该被视为一个单位。我希望
更喜欢使用re.split，但是几小时后还没写好工作
的工作。
例如：
" a（bc）d [efg] h i"
应分拆为
[" a"，"（bc）"，" d"，" [efg]"" h"，" i"]
因为速度是一个要考虑的因素，最好是有一行
正则表达式可以处理这个问题。我尝试了但失败了：
re.split（r"（？！[\（\ []。*？）\ + +（？！。*？[\} \ ]]）"，s）。它适用于（a b）c
但不起作用a（b c） :(
任何提示？
I''ve got some strings to split. They are main words, but some words
are inside a pair of brackets and should be considered as one unit. I
prefer to use re.split, but haven''t written a working one after hours
of work.
Example:
"a (b c) d [e f g] h i"
should be splitted to
["a", "(b c)", "d", "[e f g]", "h", "i"]
As speed is a factor to consider, it''s best if there is a single line
regular expression can handle this. I tried this but failed:
re.split(r"(?![\(\[].*?)\s+(?!.*?[\)\]])", s). It work for "(a b) c"
but not work "a (b c)" :(
Any hint?
推荐答案
re.findall（''\ （[^ \]] * \）| \ [[^ \]] * | \ S +''，s）
Qiangning Hong写道：
re.findall(''\([^\)]*\)|\[[^\]]*|\S+'', s)
Qiangning Hong wrote:
我有一些要拆分的字符串。它们是主要的词，但有些词语
在一对括号内，应该被视为一个单位。我希望
更喜欢使用re.split，但是几小时后还没写好工作
的工作。
例如：
" a（bc）d [efg] h i"
应分拆为
[" a"，"（bc）"，" d"，" [efg]"" h"，" i"]
因为速度是一个要考虑的因素，最好是有一行
正则表达式可以处理这个问题。我尝试了但失败了：
re.split（r"（？！[\（\ []。*？）\ + +（？！。*？[\} \ ]]）"，s）。它适用于（a b）c
但不起作用a（b c） :(
任何提示？
I''ve got some strings to split. They are main words, but some words
are inside a pair of brackets and should be considered as one unit. I
prefer to use re.split, but haven''t written a working one after hours
of work.
Example:
"a (b c) d [e f g] h i"
should be splitted to
["a", "(b c)", "d", "[e f g]", "h", "i"]
As speed is a factor to consider, it''s best if there is a single line
regular expression can handle this. I tried this but failed:
re.split(r"(?![\(\[].*?)\s+(?!.*?[\)\]])", s). It work for "(a b) c"
but not work "a (b c)" :(
Any hint?
呃，
.... | \ [[^ \]] * \] | ...
^ _ ^
faulkner写道：
er,
....|\[[^\]]*\]|...
^_^
faulkner wrote:
re.findall（''\（[^ \）] * \）| \ [[^ \]] * | \ S +''，s）< br $>
Qiangning Hong写道：
re.findall(''\([^\)]*\)|\[[^\]]*|\S+'', s)
Qiangning Hong wrote:
我有一些字符串需要拆分。它们是主要的词，但有些词语
在一对括号内，应该被视为一个单位。我希望
更喜欢使用re.split，但是几小时后还没写好工作
的工作。
例如：
" a（bc）d [efg] h i"
应分拆为
[" a"，"（bc）"，" d"，" [efg]"" h"，" i"]
因为速度是一个要考虑的因素，最好是有一行
正则表达式可以处理这个问题。我尝试了但失败了：
re.split（r"（？！[\（\ []。*？）\ + +（？！。*？[\} \ ]]）"，s）。它适用于（a b）c
但不起作用a（b c） :(
任何提示？
I''ve got some strings to split. They are main words, but some words
are inside a pair of brackets and should be considered as one unit. I
prefer to use re.split, but haven''t written a working one after hours
of work.
Example:
"a (b c) d [e f g] h i"
should be splitted to
["a", "(b c)", "d", "[e f g]", "h", "i"]
As speed is a factor to consider, it''s best if there is a single line
regular expression can handle this. I tried this but failed:
re.split(r"(?![\(\[].*?)\s+(?!.*?[\)\]])", s). It work for "(a b) c"
but not work "a (b c)" :(
Any hint?
faulkner写道：
faulkner wrote:
re.findall（''\（[^ \）] * \）| \ [[^ \]] * | \ S +''，s）
re.findall(''\([^\)]*\)|\[[^\]]*|\S+'', s)
对不起，我忘了给出限制：如果一个字母在括号旁边，
它们应该被视为一个单词。即：
a（b c）d变为[a（b c），d]
因为a与a之间没有空白。和（
sorry i forgot to give a limitation: if a letter is next to a bracket,
they should be considered as one word. i.e.:
"a(b c) d" becomes ["a(b c)", "d"]
because there is no blank between "a" and "(".
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