表现 - 0滴答??? [英] Performance - 0 ticks ???
问题描述
按照我的代码检查性能
double a = r.Next（9）* 1e307;
DateTime d = DateTime.Now;
double b = Math.Pow（a，1 /（double）100）;
TimeSpan tm = DateTime.Now - d;
Console.WriteLine（" {0} --- {1}"，b，tm.Ticks）;
返回值是0蜱虫 - 它不可能！有什么问题？
-
Tamir Khason
你想要dot.NET吗？只需询问：
"请， www.dotnet.us
Follow the code I have to check the performance
double a = r.Next(9)*1e307;
DateTime d = DateTime.Now;
double b = Math.Pow(a,1/(double)100);
TimeSpan tm = DateTime.Now - d;
Console.WriteLine("{0}---{1}",b,tm.Ticks);
The return value is 0 Ticks - IT CAN NOT BE !!! What is the problem?
--
Tamir Khason
You want dot.NET? Just ask:
"Please, www.dotnet.us "
推荐答案
Tamir Khason< ta ********** @ tcon-NOSPAM.co.il>写道：
Tamir Khason <ta**********@tcon-NOSPAM.co.il> wrote:
按照我的代码检查性能
double a = r.Next（9）* 1e307;
DateTime d = DateTime.Now;
双b = Math.Pow（a，1 /（double）100）;
TimeSpan tm = DateTime.Now - d;
Console.WriteLine（" {0} --- {1}"，b，tm.Ticks）;
返回值为0 Ticks - IT不能！有什么问题？
Follow the code I have to check the performance
double a = r.Next(9)*1e307;
DateTime d = DateTime.Now;
double b = Math.Pow(a,1/(double)100);
TimeSpan tm = DateTime.Now - d;
Console.WriteLine("{0}---{1}",b,tm.Ticks);
The return value is 0 Ticks - IT CAN NOT BE !!! What is the problem?
问题是它花费的时间比
计时器的粒度要少。做一百万次操作，时间，然后除以
a $。
-
Jon Skeet - < ; sk *** @ pobox.com>
http：//www.pobox .com / ~siget
如果回复小组，请不要给我发邮件
The problem is that it''s taking less time than the granularity of the
timer. Do the operation a million times, time that, and then divide by
a million.
--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too
谢谢你这个有用了怎么可以在没有多路复用的情况下计算这么小的
操作？
-
Tamir Khason
您想要dot.NET吗？只需询问：
"请， www.dotnet.us
" Jon Skeet [C＃MVP]" < SK *** @ pobox.com>在消息中写道
新闻：MP ************************ @ msnews.microsoft.c om ...
Thank you this works, however how it is possible to count such small
operations without multiplexing them?
--
Tamir Khason
You want dot.NET? Just ask:
"Please, www.dotnet.us "
"Jon Skeet [C# MVP]" <sk***@pobox.com> wrote in message
news:MP************************@msnews.microsoft.c om...
Tamir Khason< ta ********** @ tcon-NOSPAM.co.il>写道：
Tamir Khason <ta**********@tcon-NOSPAM.co.il> wrote:
按照我的代码检查性能
double a = r.Next（9）* 1e307;
DateTime d = DateTime.Now;
双b = Math.Pow（a，1 /（double）100）;
TimeSpan tm = DateTime.Now - d;
Console.WriteLine（" {0} --- {1}"，b，tm.Ticks）;
返回值为0 Ticks - IT不能！有什么问题？
Follow the code I have to check the performance
double a = r.Next(9)*1e307;
DateTime d = DateTime.Now;
double b = Math.Pow(a,1/(double)100);
TimeSpan tm = DateTime.Now - d;
Console.WriteLine("{0}---{1}",b,tm.Ticks);
The return value is 0 Ticks - IT CAN NOT BE !!! What is the problem?
问题是它花费的时间少于
计时器的粒度。做手术一百万次，时间，然后除以一百万。
- Jon Skeet - < sk *** @ pobox.com>
http://www.pobox.com/~skeet
The problem is that it''s taking less time than the granularity of the
timer. Do the operation a million times, time that, and then divide by
a million.
--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too
Tamir Khason< ta ********** @ tcon -NOSPAM.co.il>写道：
Tamir Khason <ta**********@tcon-NOSPAM.co.il> wrote:
谢谢你这个有用，但是怎么可以算这么小的操作而不需要多路复用呢？
Thank you this works, however how it is possible to count such small
operations without multiplexing them?
嗯，有高分辨率性能计数器，记录在
各个地方（我没有链接） - 但说实话，那就是
将受到其他因素的显着影响，例如当时计算机上还发生了什么？b $ b。定时一个非常快的
操作通常是一个坏主意。
-
Jon Skeet - < sk ** *@pobox.com>
http://www.pobox.com/~双向飞碟
如果回复小组，请不要给我发邮件
Well, there''s the high resolution performance counter, documented in
various places (I don''t have a link to hand) - but to be honest, that''s
going to be influenced significantly by other things, such as what else
is happening on the computer at the time. Timing a single very fast
operation is generally a bad idea.
--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too
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