如何纠正代码段????????????? [英] How to correct the code segment?????????????
问题描述
for（i = 0; i< 256; i ++）
{
hist [i] = 0;
}
for（i = 0; i< height; i ++）
{
for（j = 0; j< width; j ++）
{
k =（long int）rgb1 [i] [j];
hist [k] = hist [k] +1;
}
}
for（i = 0; i< 256; i ++）
{
if（hist [i]！= 0）
tmp ++;
else continue;
}
sum_hist =（int **）malloc（tmp * sizeof（int *））;
for（i = 0; i< tmp; i ++）
sum_hist [i] =（int *）malloc（2 * sizeof（int））;
for（i = 0; i< 256; i ++）
{
if（hist [i]！= 0）
{
// printf（"％d％） d \ n"，i，hist [i]）;
sum_hist [i] [0] =（int）i;
sum_hist [i] [1] =（int）hist [i];
printf（"％d％d \ n"，sum_hist [i] [0]，sum_hist [i] [1]）;
}
else继续;
}
for（i = 0; i< tmp; i ++）
printf（"％d \ n"，sum_hist [i] [1]）;
在上面的代码段中，sum_hist是一个类型为long的双指针
int ...问题是当sum_hist的值打印时没有
是块...正在给出正确的结果..但是当外面的
循环......打印出来的值......错误的值被打印.....如何
更正代码...
for(i=0;i<256;i++)
{
hist[i]=0;
}
for(i=0;i<height;i++)
{
for(j=0;j<width;j++)
{
k=(long int)rgb1[i][j];
hist[k]=hist[k]+1;
}
}
for(i=0;i<256;i++)
{
if(hist[i]!=0)
tmp++;
else continue;
}
sum_hist=(int**)malloc(tmp*sizeof(int*));
for(i=0;i<tmp;i++)
sum_hist[i]=(int*)malloc(2*sizeof(int));
for(i=0;i<256;i++)
{
if(hist[i]!=0)
{
//printf("%d %d\n",i,hist[i]);
sum_hist[i][0]=(int)i;
sum_hist[i][1]=(int)hist[i];
printf("%d %d\n",sum_hist[i][0],sum_hist[i][1]);
}
else continue;
}
for(i=0;i<tmp;i++)
printf("%d\n",sum_hist[i][1]);
In the above code segment sum_hist is a double pointer of type long
int...the problem is that when the values of sum_hist is printed withn
the is block..it is giving correct result..but when outside the for
loop..the value is printed......wrong values are printed.....how to
correct the code...
推荐答案
2008-09-13，biplab< ge ***** **@gmail.com写道：
On 2008-09-13, biplab <ge*******@gmail.comwrote:
for（i = 0; i< 256; i ++）
{
hist [i] = 0;
}
for(i=0;i<256;i++)
{
hist[i]=0;
}
您需要修改格式。建议在Usenet上发布2空格缩进
。在任何情况下，都要与
保持一致，并在操作员周围使用空格。
此外，这可以替换为：
memset （hist，0,256）;
或者可能：
memset（hist，0，sizeof hist）;
You need to fix your formatting. 2-space indents are
recommended for posting on Usenet. In any case, be
consistent, and use whitespace around operators.
Also, this could be replaced with:
memset(hist, 0, 256);
Or potentially:
memset(hist, 0, sizeof hist);
for（i = 0; i< height; i ++）
{
for（j = 0; j< width; j ++）
{
k =（long int）rgb1 [i] [j];
for(i=0;i<height;i++)
{
for(j=0;j<width;j++)
{
k=(long int)rgb1[i][j];
为什么要演员？你在这里使用k的方式，它所有的逻辑
值都可以放入unsigned char中。当然那么它已经是什么类型的b $ b就足够了？
Why this cast? The way you use k here, all its logical
values could fit into an unsigned char. Surely then
whatever type it already was, is sufficient?
hist [k] = hist [k] +1;
}
}
for（i = 0; i< 256; i ++）
{
if（hist [i]！= 0）
tmp ++;
else continue;
hist[k]=hist[k]+1;
}
}
for(i=0;i<256;i++)
{
if(hist[i]!=0)
tmp++;
else continue;
else行是多余的。修复你的格式。
The else line is superfluous. Fix your formatting.
}
sum_hist =（int **）malloc（tmp * sizeof（int *）） ;
}
sum_hist=(int**)malloc(tmp*sizeof(int*));
不要强制转换malloc（）。不要使用返回
malloc（）而不检查它是否为NULL。不要将类型传递给
sizeof。
Don''t cast the return of malloc(). Don''t use the return of
malloc() without checking it for NULL. Don''t pass types to
sizeof.
for（i = 0; i< tmp; i ++）
sum_hist [i] =（int *）malloc（2 * sizeof（int））;
for(i=0;i<tmp;i++)
sum_hist[i]=(int*)malloc(2*sizeof(int));
同上。
Ditto.
for（i = 0; i< 256; i ++）
{
if（hist [i]！= 0）
{
// printf（"％d％d \ n"，i，hist [i]）;
for(i=0;i<256;i++)
{
if(hist[i]!=0)
{
//printf("%d %d\n",i,hist[i]);
不要在usenet上使用单行注释，尤其是当你使用随机和过度的缩进方案时。
。 />
Don''t use single-line comments on usenet, especially when
you are using a random and excessive indentation scheme.
sum_hist [i] [0] =（int）i;
sum_hist [i] [1] =（int）hist [i] ;
sum_hist[i][0]=(int)i;
sum_hist[i][1]=(int)hist[i];
这些演员阵容有什么用？
What''s with these casts?
printf（"％d％d \ n"，sum_hist [i] [0]，sum_hist [i] [1]）;
}
else继续;
printf("%d %d\n",sum_hist[i][0],sum_hist[i][1]);
}
else continue;
此行是多余的。
This line is superfluous.
}
for（i = 0; i< tmp; i ++）
printf（"％d \ n"，sum_hist [i] [1]）;
上面的代码段sum_hist是一个long类型的双指针
int ...问题是当sum_hist的值用$
打印时，就是block..it是给出正确的结果..但是当外面的
循环...打印出来的值......错误的值被打印.....如何
更正代码...
}
for(i=0;i<tmp;i++)
printf("%d\n",sum_hist[i][1]);
In the above code segment sum_hist is a double pointer of type long
int...the problem is that when the values of sum_hist is printed withn
the is block..it is giving correct result..but when outside the for
loop..the value is printed......wrong values are printed.....how to
correct the code...
修复上述问题并发布可编辑的细分部分代码那么
我们会看到问题所在。
-
Andrew Poelstra ap ******* @ wpsoftware.com
要给我发电子邮件，请使用.com设置为的上述电子邮件地址.net
Fix the above issues and post a compilable "segment" of code. Then
we will see what the problem is.
--
Andrew Poelstra ap*******@wpsoftware.com
To email me, use the above email addresss with .com set to .net
2008-09-13，biplab< ge ******* @ gmail.comwrote：
On 2008-09-13, biplab <ge*******@gmail.comwrote:
>
< code snipped>
在上面的代码段中，sum_hist是long类型的双指针
int ...问题是，当sum_hist的值打印出来时，
是块...它给出了正确的结果..但是当在
$之外时b $ b loop ..打印的值......打印错误的值.....如何
更正代码...
>
<code snipped>
In the above code segment sum_hist is a double pointer of type long
int...the problem is that when the values of sum_hist is printed withn
the is block..it is giving correct result..but when outside the for
loop..the value is printed......wrong values are printed.....how to
correct the code...
这是你的代码，针对（主要是文体）问题进行了更正我提到了b $ b提到的其他问题。现在我非常清楚
问题是什么。我希望你也清楚：
/ *开始无法编译的段* /
memset（hist，0,256）;
for（i = 0; i< height; i ++）
for（j = 0; j< width; j ++）
{
k = rgb1 [i] [j];
if（hist [k] == 0）
++ count ;
++ hist [k];
}
sum_hist = malloc（count * sizeof * sum_hist）;
i $ 0; i< count; i ++）
sum_hist [i] = malloc（2 * sizeof * sum_hist [i]）;
for（i = 0; i< 256; i ++）
if（hist [i]！= 0）
{
/ * printf（"％d％d \ n"，i，hist [i]）; * /
sum_hist [i] [0] = i;
sum_hist [i] [1] = hist [i];
printf （"％d％d \ n"，sum_hist [i] [0]，sum_hist [i] [1]）;
}
for（i = 0; i< count; i ++）
printf（"％d \ nn"，sum_hist [i] [1]）;
/ *结束段* /
-
Andrew Poelstra ap ******* @ wpsoftware.com
要给我发电子邮件，请使用.com设置为.net
的上述电子邮件地址
Here is your code, corrected for the (mainly stylistic) issues I
mentioned else thread. It is abundantly clear to me now what the
problem is. I hope it is also clear to you:
/* Begin uncompilable segment */
memset(hist, 0, 256);
for(i = 0; i < height; i++)
for(j = 0; j < width; j++)
{
k = rgb1[i][j];
if(hist[k] == 0)
++count;
++hist[k];
}
sum_hist = malloc(count * sizeof *sum_hist);
for(i = 0; i < count; i++)
sum_hist[i] = malloc(2 * sizeof *sum_hist[i]);
for(i = 0; i < 256; i++)
if(hist[i] != 0)
{
/* printf("%d %d\n", i, hist[i]); */
sum_hist[i][0] = i;
sum_hist[i][1] = hist[i];
printf("%d %d\n", sum_hist[i][0], sum_hist[i][1]);
}
for(i = 0; i < count; i++)
printf("%d\n", sum_hist[i][1]);
/* End segment */
--
Andrew Poelstra ap*******@wpsoftware.com
To email me, use the above email addresss with .com set to .net
2008-09-13，Andrew Poelstra< ap ******* @ supernova.homewrote：
On 2008-09-13, Andrew Poelstra <ap*******@supernova.homewrote:
On 2008-09-13，biplab< ge ******* @ gmail.comwrote：
On 2008-09-13, biplab <ge*******@gmail.comwrote:
>>
< code snipped> ;
在上面的代码段中，sum_hist是long
int类型的双指针...问题是当sum_hist的值打印时，
是块。 .it给出了正确的答案结果..但是当外面的
循环......打印出来的值......打印错误值.....如何更正代码...
>>
<code snipped>
In the above code segment sum_hist is a double pointer of type long
int...the problem is that when the values of sum_hist is printed withn
the is block..it is giving correct result..but when outside the for
loop..the value is printed......wrong values are printed.....how to
correct the code...
这是你的代码，针对（主要是文体）问题进行了更正我提到了b $ b提到的其他线程。现在我非常清楚
问题是什么。我希望你也清楚：
/ *开始无法编译的段* /
memset（hist，0,256）;
for（i = 0; i< height; i ++）
for（j = 0; j< width; j ++）
{
k = rgb1 [i] [j];
if（hist [k] == 0）
++ count ;
++ hist [k];
}
sum_hist = malloc（count * sizeof * sum_hist）;
i $ 0; i< count; i ++）
sum_hist [i] = malloc（2 * sizeof * sum_hist [i]）;
Here is your code, corrected for the (mainly stylistic) issues I
mentioned else thread. It is abundantly clear to me now what the
problem is. I hope it is also clear to you:
/* Begin uncompilable segment */
memset(hist, 0, 256);
for(i = 0; i < height; i++)
for(j = 0; j < width; j++)
{
k = rgb1[i][j];
if(hist[k] == 0)
++count;
++hist[k];
}
sum_hist = malloc(count * sizeof *sum_hist);
for(i = 0; i < count; i++)
sum_hist[i] = malloc(2 * sizeof *sum_hist[i]);
我忘了添加malloc（）不返回NULL的检查。
I forgot to add checks that malloc() does not return NULL.
for（i = 0; i< 256 ; i ++）
if（hist [i]！= 0）
{
/ * printf（"％d％d \ n，i，hist [i]）; * /
sum_hist [i] [0] = i;
for(i = 0; i < 256; i++)
if(hist[i] != 0)
{
/* printf("%d %d\n", i, hist[i]); */
sum_hist[i][0] = i;
对于OP，当我超过计数时会发生什么？
To the OP, what happens when i exceeds count?
sum_hist [i] [1] = hist [i];
printf（"％d％d \ n"，sum_hist [i] [0]，sum_hist [i] [1]）;
}
for（i = 0; i< count; i ++）
printf（"％d \ n"，sum_hist [i ] [1]）;
/ *结束段* /
sum_hist[i][1] = hist[i];
printf("%d %d\n", sum_hist[i][0], sum_hist[i][1]);
}
for(i = 0; i < count; i++)
printf("%d\n", sum_hist[i][1]);
/* End segment */
-
Andrew Poelstra ap*******@wpsoftware.com
给我发电子邮件，使用.com设置为.net
--
Andrew Poelstra ap*******@wpsoftware.com
To email me, use the above email addresss with .com set to .net
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