在包含两者的字符串中拆分数字和字母 [英] Splitting numbers and letters in string which contains both

问题描述

我正在尝试拆分以下（或类似）字符串08-27-2015 07:25:00 AM。
目前我使用

I am trying to split following (or similar) string "08-27-2015 07:25:00AM". Currently I use

var parts = date.split(/[^0-9a-zA-Z]+/g);

导致

["02", "27", "2012", "03", "25", "00AM"]

问题在于 00AM 部分。我希望它也能分开。所以完美的结果将是：

The problem is with the 00AM part. I want it to be separated too. So the perfect result would be:

["02", "27", "2012", "03", "25", "00", "AM"]

推荐答案

如果你正在寻找字母或数字的序列，但不是混合的序列，你可以这样做...

If you're looking for sequences of letters or numbers, but not a sequence both mixed, you can do this...

"08-27-2015 07:25:00AM".match(/[a-zA-Z]+|[0-9]+/g)

导致......

["08", "27", "2015", "07", "25", "00", "AM"]

开在 | 的任一侧，我们有一个或多个字母的序列和一个或多个数字的序列。因此，当它出现一封信时，它会收集所有连续的字母，直到它达到非字母，此时它会收集所有连续的数字，依此类推。

On either side of the |, we have a sequence of one or more letters and a sequence of one or more numbers. So when it comes across a letter, it will gather all contiguous letters until it reaches a non-letter, at which point it gathers all contiguous numbers, and so on.

任何其他字符都不匹配，因此它不会成为结果的一部分。

Any other character simply doesn't match so it doesn't become part of the result.

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