删除两个词典之间的常用条目 [英] Delete common entries between two dictionaries
问题描述
我在这个留言板上得到了很好的帮助。我想知道我是否可能会在这方面得到更多的帮助。
我正处于我有两个词典的地方，有关于一个
域名和该域名的频率。
既然我有两个，我想删除两个中的每个条目
有共同点，只留下字典中唯一的那些？
我说有一个名为domains_black的词典
和另一个domains_white。 ..
感谢您的帮助。
I have received such good help on this message board. I wonder if I might
not get a little more help from you on this.
I am at the point where I have two dictionaries, with information of a
domain and a frequency of that domain.
Now that I have the two, I want to delete each entry from one that the two
have in common, leaving only those that are unique to the dictionary?
Say I have a dictionary called domains_black
and another domains_white...
Thanks for the help.
推荐答案
2003年11月24日星期一13:24:17 -0800，Amy G写道：
On Mon, 24 Nov 2003 13:24:17 -0800, Amy G wrote:
我在这个留言板上得到了很好的帮助。我想知道我是否可能在这方面得不到你的帮助。
我正处于有两个字典的地方，有一个域名和一个域名的信息该领域的频率。
现在我有两个，我想删除两个共同的一个条目，只留下那些独特的条目
字典？
如果套装适当地为你的数据建模，这对套装来说会很棒。
（有两套，这只是（s1-（s1& s）。 s2）））
说我有一个名为domains_black的词典和另一个
domains_white ...
I have received such good help on this message board. I wonder if I
might not get a little more help from you on this.
I am at the point where I have two dictionaries, with information of
a domain and a frequency of that domain.
Now that I have the two, I want to delete each entry from one that
the two have in common, leaving only those that are unique to the
dictionary?
This would be great for sets, if a set adequately models your data.
(with two sets, this would simply be (s1-(s1&s2)))
Say I have a dictionary called domains_black and another
domains_white...
你想要定义吗？按键或键（键，值）对等等？
对于domains_white.keys（）中的键，
：
如果在domains_black中键入
：del domains_black [key ]
表示domains_white.keys（）中的键：
如果在domains_black和domains_white [key]中键入== domains_black [key]：
del domains_black [key]
-D
-
嘲笑指令的人将会支付它，
但尊重命令的人会得到回报。
箴言13:13
www： http://dman13.dyndns.org/~dman/ jabber： DM ** @ dman13.dyn dns.org
Did you want to define equality by key or by (key, value) pair?
for key in domains_white.keys() :
if key in domains_black: del domains_black[key]
for key in domains_white.keys() :
if key in domains_black and domains_white[key] == domains_black[key] :
del domains_black[key]
-D
--
He who scorns instruction will pay for it,
but he who respects a command is rewarded.
Proverbs 13:13
www: http://dman13.dyndns.org/~dman/ jabber: dm**@dman13.dyndns.org
" Amy G" <是******* @ cox.net>写道：
"Amy G" <am*******@cox.net> writes:
既然我有两个，我想从两个共同的条目中删除每个条目，只留下字典中唯一的条目吗？
说我有一个名为domains_black的词典
和另一个domains_white ...
Now that I have the two, I want to delete each entry from one that the two
have in common, leaving only those that are unique to the dictionary?
Say I have a dictionary called domains_black
and another domains_white...
for domains_white（）：
如果domain_black中的k：
del domains_black [k]
for k in domains_white():
if k in domains_black:
del domains_black[k]
文章< 97 ********** **@dman13.dyndns.org>，
德里克''dman''哈德森< dm ** @ dman13.dyndns.org>写道：
In article <97************@dman13.dyndns.org>,
Derrick ''dman'' Hudson <dm**@dman13.dyndns.org> wrote:
如果一组充分模拟你的数据，这对集合来说会很棒。
（有两组，这只是（s1-（s1& s2）） ））
This would be great for sets, if a set adequately models your data.
(with two sets, this would simply be (s1-(s1&s2)))
你的意思是s1 - s2，不需要额外的& ;.
-
David Eppstein http://www.ics.uci.edu/ ~eppstein /
大学加州，欧文，信息学院和计算机科学
You mean s1 - s2, no need for that extra &.
--
David Eppstein http://www.ics.uci.edu/~eppstein/
Univ. of California, Irvine, School of Information & Computer Science
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