如何在C ++中添加用户输入数组中的每个第n位？ [英] How to add every nth digit in a user input array in C++ ?

问题描述

c ++中的代码。

假设我输入一个数组，我想跳过每个第d位并在离开每个第d位后计算总和。然后我的代码将是？

for（i = 0; i< n; i + d）

{

add + = i; < br $>
}



我尝试过：

  for （i =  0 ; i< n; i + d）
 {
 add + = i; 
} 

解决方案

首先考虑老师为您设置的问题：您显示的代码将无效（a; b; d）
c; <

 / pre> 
 
a在循环之前执行一次并允许你设置启动条件。​​
 
b每个循环执行一次以检查它是否应该循环并且执行主体（c）。
 $ $ bc每次循环时执行一次。
 
d在（c）之后立即执行并为下一次设置条件圆形。
 
例如，要打印数组的五个元素：
 
 
  for （i =  0 ; i<  5 ，i ++）
 cout<< ; arr [i]; 
但是一旦你初始化它，你显示的代码就不会改变 i ，所以循环永远不会结束。 
 
如果你改写它会开始工作：
 
 
   （i =  0 ; i< n; i + = d）
但您仍然希望在循环内访问您的数组数据索引值... 

您的代码

• 不访问数组。
• Doesn' t跳过每个 d 周期。

。





要访问数组，您可以将其编入索引：

 sum + = a [i] 
 

要跳过每个 d 周期，你可以使用 if

  if （（i％d）！=（d-  1 ））
 {
  //   not-skipping cod e  
} 

code in c++.
suppose i input an array and i want to skip every dth digit and calculate the sum after leaving every dth digit. Then my code would be ?
for(i=0;i<n;i+d)
{
add+=i;
}

What I have tried:

for(i=0;i<n;i+d)
{
add+=i;
}

解决方案

Start by thinking about the problem your teacher set you: the "code" you show won't work, or even ever finish.

for (a; b; d)
   c;

a is executed once, before the loop and lets you set up the start conditions.
b is executed once per loop to check if it should go round and execute the body (c).
c is executed once each time the loop goes round.
d is executed immediately after (c) and sets up teh conditions for teh next time round.
For example, to print five elements of an array:

for (i = 0; i < 5, i++)
   cout << arr[i];

But the code you show doesn't change i at all once you have initialised it, so the loop will never end.
It would start to work if you wrote this instead:

for (i = 0; i < n; i += d)

But you would still want to access your array data inside the loop instead of the index value ...

Your code

• Doesn't access the array.
• Doesn't skip every d cycles.

.


To access the array you may index it:

sum += a[i]

To skip at every d cycle you could use an if

if ( (i % d) != (d-1) )
{
  // not-skipping code
}

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