在这段代码中，{if（（scanf（"％d"，& a [I]）== 1））C ++;做什么和'== 1'检查 [英] In this code what is { if((scanf("%d", &a[I])==1)) C++; } doing and what is '==1' checking
问题描述
{
int a [50];
int i，j，c = 0;
printf（输入输入\ n） ;
for（i = 0; i< 50; i ++）
{
if（（scanf（％d） ，& a [i]）== 1））
c ++;
}
printf（No。输入是％d，c）;
返回0;
}
我是什么试过：
c程序找不到。插入后数组中的输入，插入时不计数。
{
int a[50];
int i,j,c=0;
printf("enter the inputs\n");
for(i=0;i<50;i++)
{
if((scanf("%d",&a[i])==1))
c++;
}
printf("No. of inputs are %d",c);
return 0;
}
What I have tried:
c program to find the no. of inputs in an array after inserting and without counting while inserting.
推荐答案
分解：
Break it down:
if((scanf("%d",&a[i])==1))
c++;从内心开始：
Start with the inner most:
&a[i]数组中第i个元素的地址。每次代码绕循环，这都会改变。
Address of the "i"th element on the array. Each time the code goes round the loop, this changes.
scanf("%d",&a[i])这是一个标准库函数： scanf - C ++ Reference [ ^ ]它根据格式从标准输入读取。在这种情况下，格式为％d，表示读取十进制整数第二个参数是您要存储值的地址。
This is a standard library function: scanf - C++ Reference[^] it reads from the standard input, according to the format. in this case, the format is %d which means "read a decimal integer" The second parameter is the address of the place you want to store the value.
if((scanf("%d",&a[i])==1))
...如果scanf函数成功读取一个整数，则执行下一个语句或语句块。
If the scanf function successfully read one integer, then execute the next statement or statement block.
c++增加 c 一个。
所以...它从用户读取整数，将它们存储在数组中，并对它们进行计数。
Increment c by one.
So...it reads integers from the user, stores them in and array, and counts them.
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