一个程序，它有一个名为polar_to_rect（）的函数，它将极坐标向量转换为矩形向量？ [英] A program that has a function called polar_to_rect() that converts a polar vector to a rectangular vector？

问题描述

好吧，我不知道如何修复错误，在最后一行说mag不能用作函数。如果有更多错误，请帮助我



我尝试过：

OKay, I'm dont know how to fix the error where it says "mag cannot be used as a function" in the last line. AND if there are more errors please help me

What I have tried:

#include<iostream>
#include<cmath>
using namespace std;

void polar_to_rect(double&, double&, double , double );

int main()                                           
{               
    char ch;                                         
    double mag, angle, x, y;
    
    
    cout<<"           This program converts  a polar vector to a rectangular vector.."<<endl<<endl;
    
    while (ch != 'n')
    {
          cout<<"Enter the value of mag: ";      
          cin>>mag;
          cout<<"Enter the value of angle: ";
          cin>>angle;
          
          
          polar_to_rect(mag,angle, x, y);
          cout<<"                            >>x = "<<x<<endl;
          cout<<"                            >>y= "<<y<<endl<<endl;
          cout<<"Another calculation? (y/n)... ";
          cin>>ch;
    }
    
    
    return 0;                                      
}  

void polar_to_rec(double _mag, double angle, double &x, double &y)
{     
      x = _mag(cos(angle));
      y = _mag(sin(angle));
      
      return;
}

推荐答案

C ++ 不接受标准数学表达式（省略乘法运算符）你必须使用有效的 C ++ 表达式

C++ doesn't accept standard mathematical expressions (where the multiplication operator is omitted) you have to use valid C++ expressions

Quote：

x = _mag（cos（angle））;

y = _mag（sin（angle））;

x = _mag(cos(angle));
y = _mag(sin(angle));

应该是

should be

x = _mag * cos(angle);
y = _mag * sin(angle);

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