如何转换十六进制字符串转换成有符号整数？ [英] How do I convert hex string into signed integer?

问题描述

我越来越需要被转换为符号的8位整数，一个十六进制字符串。目前我将使用的Int16 /的Int32，这显然不会给我一个负值为8位整数。如果我在十六进制值255，我该如何将其转换为-1十进制？我以为我想使用一个为sbyte，但我不知道怎么去的价值有正确的。

I'm getting a hex string that needs to be converted to a signed 8-bit integer. Currently I'm converting using Int16/Int32, which will obviously not give me a negative value for an 8-bit integer. If I get the value 255 in Hex, how do I convert that to -1 in decimal? I assume I want to use an sbyte, but I'm not sure how to get that value in there properly.

推荐答案

我的解决办法是把先取前8位的16位整数，并将其存储在一个为sbyte。

My solution was to put the first take the first 8 bits of the 16 bit integer and store them in an sbyte.

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