从字符串中删除重复项并计算每个项的出现次数 [英] Remove duplicate items from string and count occurrence of each item
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问题描述
我有一个字符串
string chars = A | A | B | A + | C | B + | A + | C | A | B + | B;
来自上面的字符串我想删除重复的项目并计算每个独特项目的出现次数。
结果应该类似于>>答:3; A +:2; B:2; B +:2; C:2
我想用C#实现上述目标。
谢谢试试这个:
chars = A | A | B | A + | C | B + | A + | C | A | B + | B跨度>;
string output = string .Join( ;,chars.Split(' |')
.GroupBy(x = > x)
.OrderBy(x = > x.Key)
。选择(x = > string .Format( {0}:{1},x.Key,x。计数())));
Console.WriteLine(输出);
输出: A:3; A +:2; B:2; B +:2; C:2
Linq方法非常简单:
string chars = A | A | B | A + | C | B + | A + | ç| A | B + | B跨度>;
string [] sep = chars.Split(' |'跨度>);
List< string> withCount = sep.GroupBy(s = > s)。选择(g = > g.Key + : + g.Count())。ToList();
foreach ( string s in withCount)
{
Console.WriteLine(s);
}
I have a string
string chars = "A|A|B|A+|C|B+|A+|C|A|B+|B";
from above string I would like to remove duplicate items and count occurrence of each unique item.
Result should be like >> A: 3; A+: 2; B: 2; B+: 2; C: 2
I would like to achieve above in C#.
Thanks in advance.
解决方案
Try this:
string chars = "A|A|B|A+|C|B+|A+|C|A|B+|B"; string output = string.Join("; ", chars.Split('|') .GroupBy(x => x) .OrderBy(x => x.Key) .Select(x => string.Format("{0}: {1}", x.Key, x.Count()))); Console.WriteLine(output);
Output:A: 3; A+: 2; B: 2; B+: 2; C: 2
Linq methods make it pretty simple:
string chars = "A|A|B|A+|C|B+|A+|C|A|B+|B"; string[] sep = chars.Split('|'); List<string> withCount = sep.GroupBy(s => s).Select(g => g.Key+ " : " + g.Count()).ToList(); foreach (string s in withCount) { Console.WriteLine(s); }
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