如何通过代码打开手机的无线网络功能？ [英] How to turn on wireless network feature of phone by code?

问题描述

如果我没有使用此功能，我无法获得纬度和经度。

当我启用设置>位置>使用无线网络（开启）时的功能

我可以获得纬度经度...



有没有其他方法可以解决这个问题？

任何打开功能的sammple代码





我可以打开GPS卫星...

I am not getting latitude and longitude without this feature from GPS.
when I turn on feature which is on Settings>location>Use Wireless Network(On)
I can get latitude longitude ...

Is there any other way to solve this?
Any sammple code to turn on feature


I can turn on GPS satellite by this...

Intent intent = new Intent("android.location.GPS_ENABLED_CHANGE");
intent.putExtra("enabled", true);
sendBroadcast(intent);

我的代码是为了得到纬度和经度...

My code is this to get latitude and longitude...

/**
 * For Getting Gps latitude longitude
 */

locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
Criteria criteria = new Criteria();

// Getting the name of the provider that meets the
// criteria
provider = locationManager.getBestProvider(criteria,
        false);

System.out.println(provider);


if (provider != null && !provider.equals("")) {

    // Get the location from the given provider
    Location location = locationManager
            .getLastKnownLocation(provider);

    locationManager.requestLocationUpdates(provider,
            20000, 1,this);

    System.out.println(location);

    if (location != null) {
        onLocationChanged(location);
        System.out.println(latitude + longitude);


    } else {
        System.out.println("Location not retrived...");
    }

    @Override
public void onLocationChanged(Location location) {
    // Getting reference to TextView tv_longitude
    latitude = location.getLatitude();
    longitude = location.getLongitude();
}

@Override
public void onProviderDisabled(String provider) {
    // TODO Auto-generated method stub
}

@Override
public void onProviderEnabled(String provider) {
    // TODO Auto-generated method stub
}

@Override
public void onStatusChanged(String provider, int status, Bundle extras) {
    // TODO Auto-generated method stub
}

推荐答案

你好Vivek，



这里有很好的文章[ ^ ]。基本上你需要以下权限

Hello Vivek,

There is good article on this here[^]. Basically you will need following permissions

<uses-permission android:name="android.permission.ACCESS_WIFI_STATE" xmlns:android="#unknown"></uses-permission>
<uses-permission android:name="android.permission.UPDATE_DEVICE_STATS" xmlns:android="#unknown"></uses-permission>
<uses-permission android:name="android.permission.CHANGE_WIFI_STATE" xmlns:android="#unknown"></uses-permission>
<uses-permission android:name="android.permission.WAKE_LOCK" xmlns:android="#unknown"></uses-permission>

在清单中宣布此功能后，您的应用就可以访问Wi-Fi。然后，您可以使用以下代码打开Wi-Fi

Once this is declared in the manifest your app will be able to access the Wi-Fi. You can then use following code to turn on Wi-Fi

wifiManager = (WifiManager) this.getSystemService(Context.WIFI_SERVICE); 
wifiManager.setWifiEnabled(true);
wifiManager.setWifiEnabled(false);

问候，

Regards,

这篇关于如何通过代码打开手机的无线网络功能？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！