运算符重载错误"+" [英] Operator overloading mistake '+'

问题描述

我想重载``+''运算符并通过使用vector添加两个系列的元素.但是无论何时我运行代码，向量的第一个元素都变为"inf".我不明白为什么会收到此错误.我几次检查代码是否在填充向量时是否做错了，但我无法找到任何要纠正的东西.有人对此错误有任何想法吗?这是编译后的代码和结果-> http://ideone.com/CA5Q6n [

I wanna overload ''+'' operator and add the elements of two series by using vector. But anytime I run the code , the first elements of my vectors get ''inf'' . I can''t understand why I get this error. I checked my code several time whether I had done mistake while filling vector but I coulnt find anything to correct. Anyone has any idea about this mistake? here is the compiled code and results -> http://ideone.com/CA5Q6n[^]

#include <cstdlib>
#include <iostream>
#include <vector>
#include <cmath>

using namespace std;

class Overload {
public:
    Overload();
    Overload(int);
    
    Overload operator+(Overload &) ;
    void SetK(int k);
    int GetK() const;
    void SetVect(vector<double> vect);
    vector<double> GetVect() const;
    
   
    
private:
    vector<double> vect ;
    int k ;
    

};


int main(int argc, char** argv) {
    
    Overload a,b(10),c(10) ;
    a= b+c ;
    
    cout <<"\nAdded :\n" ;
    for(unsigned int i=0;i<a.GetVect().size(); ++i)
    cout <<"Res : " << a.GetVect()[i] << endl ;   
    cout << "first element : "<< a.GetVect()[0] << endl ; 
    return 0;
}


Overload::Overload() {
    k=10 ;
    cout << "\nFrist Started\n" ;
    for(unsigned int i=0;i<k ; ++i){
        double res = 1/pow(i,2) ;
        vect.push_back(res);
        cout << vect[i] << " " ;
    }
    cout << "VEctor size : " << vect.size() << endl ;
    cout <<"\nfirst ended\n"<< endl ;
}

Overload::Overload(int k) {
    double res=0 ;
    cout << "\nsecond started : \n" ;
    for(unsigned int i=0;i<k ; ++i){
        res = 1/pow(i,2) ;
        vect.push_back(res);
        cout << vect[i] << " " ;
    }
    cout << "\nsecond ended : \n" ;
}

Overload Overload::operator+(Overload &a){
    double res=0 ;
    Overload x ;
    for(unsigned int i=0 ;i<vect.size();i++) {
        res = vect[i] + a.vect[i];
        x.vect.push_back(res) ;
    }
    return x ;
}

void Overload::SetK(int k) {
    this->k = k;
}

int Overload::GetK() const {
    return k;
}

void Overload::SetVect(vector<double> vect) {
    this->vect = vect;
}

vector<double> Overload::GetVect() const {
    return vect;
}

推荐答案

在::Overload()和::Overload(int k)中，for循环的第一次迭代都为i=0计算1/pow(i,2).这意味着您最终将除以Inf值表示的零.

Both in ::Overload() and ::Overload(int k) the first iteration of the for loop calculates 1/pow(i,2) for i=0. Which means you end up dividing by zero which is represented by the Inf value.

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