重载++运算符 [英] Overload ++ operator

问题描述

我试图在第一次处理运算符重载，我写了这个代码重载++运算符增加类变量 i 和 x by a ..
它执行的工作，但编译器显示这些警告：

I am trying to deal with operator overloading at the first time, and I wrote this code to overload ++ operator to increment class variables i and x by one.. It does the job but the compiler showed these warnings:

警告1警告C4620：没有为
找到'operator ++'的后缀形式类型'tclass'，使用前缀
形式c：\users\ahmed\desktop\cppq\cppq\\ \\ cppq.cpp 25

Warning 1 warning C4620: no postfix form of 'operator ++' found for type 'tclass', using prefix form c:\users\ahmed\desktop\cppq\cppq\cppq.cpp 25

警告2警告C4620：没有为
找到'operator ++'的后缀形式类型'tclass'，使用前缀
form c：\users\ahmed\desktop\cppq\cppq\cppq.cpp 26

Warning 2 warning C4620: no postfix form of 'operator ++' found for type 'tclass', using prefix form c:\users\ahmed\desktop\cppq\cppq\cppq.cpp 26

这是我的代码：

class tclass{
public:
    int i,x;
    tclass(int dd,int d){
        i=dd;
        x=d;
    }
    tclass operator++(){

        i++;
        x++;
        return *this;

    }
};

int main() {
    tclass rr(3,3);
    rr++;
    rr++;
    cout<<rr.x<<" "<<rr.i<<endl;
    system("pause");
    return 0;
}

推荐答案

>

This syntax:

tclass operator++()

$ b b

用于前缀 ++ （实际上通常写为 tclass& operator ++（））。要区分后缀增量，请添加一个未使用的 int 参数：

is for prefix ++ (which is actually normally written as tclass &operator++()). To distinguish the postfix increment, you add a not-used int argument:

tclass operator++(int)

c $ c> tclass& ，因为结果可能在之后使用：（++ rr）.x 。

再次注意，后缀增量看起来像这样：

Again, note that the postfix increment looks like this:

tclass operator++(int)
{
    tclass temp = *this;
    ++*this;     // calls prefix operator ++
                 // or alternatively ::operator++(); it ++*this weirds you out!!
    return temp;
}

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