比较运算符重载 [英] Comparison operator overloading

问题描述

最佳做法(在这种情况下):

Which is best practice (in this case):

bool Foo::operator==(const Foo& other) {
  return bar == other.bar;
}

// Implementation 1
bool Foo::operator!=(const Foo& other) {
  return bar != other.bar
}

// Implementation 2
bool Foo::operator!=(const Foo& other) {
  return !(*this == other);
}

对于>，<，< =，> =之类的运算符，我会尽可能采用实现2.但是，对于！=，我认为实现1更好，因为没有进行其他方法调用，这是正确的吗?

For operators like >, <, <=, >= I would go with implementation 2 when possible. However, for != I think implementation 1 is better since another method call is not made, is this correct?

推荐答案

第二个实现具有显着的约束，即==始终是与!=相对的布尔值.这可能就是您想要的，并且它使您的代码更易于维护，因为您只需更改一个实现即可使两者保持同步.

The second implementation has the notable constraint that == will always be the boolean opposite of !=. This is probably what you want, and it makes your code easier to maintain because you only have to change one implementation to keep the two in sync.

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