维修第一次计时器 [英] Servicing the first timer

问题描述

我已经启动了两个threading.timers，它具有这样的回调，在到期时被调用:

I have started two threading.timers which has callback like this called on expiry:

private void N_ArTimeoutExpired(object state)
       {
           // Timeout raised. Set timeout error state
           String message = string.Empty;
           message = "N_Ar Timer Expired at -> " + DateTime.Now.ToString("h:mm:ss.fff");
           _logger.Info(message);
           Iso15765Transport.ErrorEventArgs errorEventArgs = new Iso15765Transport.ErrorEventArgs("N_Ar timer expired");
           _owner.SetEvent(errorEventArgs);

       }

在到期时，它引发一个事件，该事件调用以下方法:

Here on expiry it raises an event which calls following method:

public void OnTimeOut(object o, ErrorEventArgs e)
       {
           lock (_locker)
           {
             
             
               string errorMsg = e._errorMsg;
               PublishErrorFrame(errorMsg);
               ResetAllTimers();
               ResetStateMachine();
               AbortCurrentReception();
             
           }

       }

我的问题是，在这种方法中，我必须维修第一个到期的计时器并拒绝另一个计时器.我该怎么做?

考虑两个计时器同时到期的情况.
我不能放一个标志，只是以这种方式检查.原因是，当第一个计时器到期时，我将重置所有状态机，并重新开始通信.可能是我有一个计时器，在重置状态机之前更早了.

My problem is that in this method i have to service the first timer that expires and reject the other one.How can i do that?

Considering a situation where both timers expires simultaneously.
I cant put a flag and simply check in that way. Reason is that when first timer expires , i reset all state machines and communication is started again. The chances are that i have a timer that expired earlier before resetting state machines.

推荐答案

我认为您正在寻找的是使用

I think what you are looking for is the use of Monitor[^].

This allows you to block the execution in the method proper, ensuring that flags you set will be set by one and only one thread at a time and thus, preventing race conditions.

Cheers.

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