从机器人到CakePHP的服务器上传图片 [英] Upload image from android to cakephp server
问题描述
目前我正在构建应用程序的版本为Web服务,所以我想通过一个应用程序来我CakePHP的web服务器从我的Android手机里上传图片。
Currently I'm working on building an app version for a web service so I trying to upload image from inside my android phone through an app to my cakephp webserver.
//安卓code
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String existingFileName = Environment.getExternalStorageDirectory().getAbsolutePath() + "/New Folder/rsz_passportphoto.jpg";
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String responseFromServer = "";
String urlString = "http://msm.icas.edu.sg/FANS/FANSweb/app/controllers/pagesext_controller.php";
try
{
//------------------ CLIENT REQUEST
FileInputStream fileInputStream = new FileInputStream(new File(existingFileName) );
// open a URL connection to the Servlet
URL url = new URL(urlString);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
System.out.println("Connected");
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + existingFileName + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.e("Debug","File is written");
fileInputStream.close();
Log.e("Debug","file input close");
dos.flush();
Log.e("Debug","flushed");
dos.close();
Log.e("Debug","closed");
}
catch (MalformedURLException ex)
{
Log.e("Debug", "error 1 : " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("Debug", "error 2: " + ioe.getMessage(), ioe);
}
//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("Debug","Server Response "+str);
}
inStream.close();
}
catch (IOException ioex){
Log.e("Debug", "error: " + ioex.getMessage(), ioex);
}
}
它总是出来
9月7日至26日:13:34.112:E /调试(810):错误:的 http://msm.icas.edu.sg/FANS/FANSweb/app/controllers/pagesext_controller.php
9月7日至26日:13:34.112:E /调试(810):java.io.FileNotFoundException:的 http://msm.icas.edu.sg/FANS/FANSweb/app/controllers/pagesext_controller.php
推荐答案
了解更多:
<一href=\"http://getablogger.blogspot.com/2008/01/android-how-to-post-file-to-php-server.html#ixzz21qi0MF72\" rel=\"nofollow\">http://getablogger.blogspot.com/2008/01/android-how-to-post-file-to-php-server.html#ixzz21qi0MF72
或尝试这种
// PHP code
//php code
<?php
$target_path = "uploads/";
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['uploadedfile']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
?>
///了Android code放在这里
///The android code goes here
import java.io.BufferedInputStream;
import java.io.DataOutputStream;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import org.apache.commons.codec.binary.Base64;
import org.apache.http.util.ByteArrayBuffer;
import android.util.Log;
public class HttpFileUploader implements Runnable{
URL connectURL;
String params;
String responseString;
InterfaceHttpUtil ifPostBack;
String fileName;
byte[] dataToServer;
HttpFileUploader(String urlString, String params, String fileName ){
try{
connectURL = new URL(urlString);
}catch(Exception ex){
Log.i("URL FORMATION","MALFORMATED URL");
}
this.params = params+"=";
this.fileName = fileName;
}
void doStart(FileInputStream stream){
fileInputStream = stream;
thirdTry();
}
FileInputStream fileInputStream = null;
void thirdTry(){
String exsistingFileName = "asdf.png";
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
String Tag="3rd";
try
{
//------------------ CLIENT REQUEST
Log.e(Tag,"Starting to bad things");
// Open a HTTP connection to the URL
HttpURLConnection conn = (HttpURLConnection) connectURL.openConnection();
// Allow Inputs
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
DataOutputStream dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + exsistingFileName +"\"" + lineEnd);
dos.writeBytes(lineEnd);
Log.e(Tag,"Headers are written");
// create a buffer of maximum size
int bytesAvailable = fileInputStream.available();
int maxBufferSize = 1024;
int bufferSize = Math.min(bytesAvailable, maxBufferSize);
byte[] buffer = new byte[bufferSize];
// read file and write it into form...
int bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// close streams
Log.e(Tag,"File is written");
fileInputStream.close();
dos.flush();
InputStream is = conn.getInputStream();
// retrieve the response from server
int ch;
StringBuffer b =new StringBuffer();
while( ( ch = is.read() ) != -1 ){
b.append( (char)ch );
}
String s=b.toString();
Log.i("Response",s);
dos.close();
}
catch (MalformedURLException ex)
{
Log.e(Tag, "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e(Tag, "error: " + ioe.getMessage(), ioe);
}
}
}
Many of the headers included in the above file is not required, i was trying and failing :).
Now to upload file here is the java code from my activity class
public void uploadFile(){
try {
FileInputStream fis =this.openFileInput(NAME_OF_FILE);
HttpFileUploader htfu = new HttpFileUploader("http://11.0.6.23/test2.php","noparamshere", NAME_OF_FILE);
htfu.doStart(fis);
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
这篇关于从机器人到CakePHP的服务器上传图片的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!