机器人，正从服务器的数据 [英] Android, getting data from server
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问题描述
我在android系统完全绿色。我想创建应用程序从服务器获取数据并显示在应用程序。谁能告诉我怎么开始呢？我试过低于这个code。但唯一的例外是显示食物是找不到的。
私人的EditText的OutputStream;@覆盖
公共无效的onCreate（捆绑savedInstanceState）{
super.onCreate（savedInstanceState）;
的setContentView（R.layout.main）;
字符串结果= NULL;
输入的InputStream = NULL;
StringBuilder的sbuilder = NULL;
的OutputStream =（EditText上）findViewById（R.id.output）;
ArrayList的＆LT;＆的NameValuePair GT; namevaluepairs中=新的ArrayList＆LT;＆的NameValuePair GT;（）; 尝试{
HttpClient的HttpClient的=新DefaultHttpClient（）;
HttpPost httppost =新HttpPost（ik.su.lt/~jbarzelis/index.php）;
httppost.setEntity（新UrlEn codedFormEntity（namevaluepairs中））;
HTT presponse响应= httpclient.execute（httppost）;
如果（response.getStatusLine（）的getStatus code（）！= 200）{
Log.d（MyApp的，服务器遇到错误）;
}
HttpEntity实体= response.getEntity（）;
输入= entity.getContent（）;
}
赶上（例外五）{
e.printStackTrace（）;
}
尝试{
的BufferedReader读者=新的BufferedReader（新InputStreamReader的（输入，ISO-8859-1），8）;
sbuilder =新的StringBuilder（）; 串线= NULL; 而（（行= reader.readLine（））！= NULL）{
sbuilder.append（行+\\ n）;
}
input.close（）;
结果= sbuilder.toString（）;
}
赶上（例外五）{
e.printStackTrace（）;
}
INT fd_id;
串fd_name;
尝试{
JSONArray jArray =新JSONArray（结果）;
JSONObject的json_data = NULL;
的for（int i = 0; I＆LT; jArray.length（）;我++）{
json_data = jArray.getJSONObject（ⅰ）;
fd_id = json_data.getInt（FOOD_ID）;
fd_name = json_data.getString（FOOD_NAME）;
outputStream.append（fd_id ++ fd_name +\\ n）;
}
}
赶上（JSONException E1）{
Toast.makeText（getBaseContext（），无食物中，Toast.LENGTH_LONG）.show（）;
}
赶上（ParseException的E1）{
e1.printStackTrace（）;
}
}
PHP code是正确的它显示的数据。我认为somethig是错误的code以上。
＆LT; PHP
mysql_connect（本地主机，********，**********）;
mysql_select_db（测试）;
$ SQL =的mysql_query（选择FOOD_NAME为Maistas食品，其中像FOOD_NAME'A％'）;
而（$行= mysql_fetch_assoc（$ SQL））$输出[] = $行;
打印（json_en code（$输出））;
mysql_close;
？＆GT;
解决方案
包com.Valluru;进口java.io.BufferedReader中;
进口的java.io.InputStream;
进口java.io.InputStreamReader中;
进口的java.util.ArrayList;
进口的java.util.List;
进口org.apache.http.HttpEntity;
进口org.apache.http.Htt presponse;
进口org.apache.http.NameValuePair;
进口org.apache.http.client.HttpClient;
进口org.apache.http.client.methods.HttpPost;
进口org.apache.http.impl.client.DefaultHttpClient;
进口org.json.JSONArray;
进口org.json.JSONException;
进口org.json.JSONObject;进口android.app.ListActivity;
进口android.content.Intent;
进口android.net.ParseException;
进口android.net.Uri;
进口android.os.Bundle;
进口android.util.Log;
进口android.view.View;
进口android.widget.AdapterView;
进口android.widget.AdapterView.OnItemClickListener;
进口android.widget.ArrayAdapter;
进口android.widget.ListView;
进口android.widget.TextView;
进口android.widget.Toast;公共类食品扩展ListActivity {
字符串结果= NULL;
InputStream为= NULL;
StringBuilder的SB = NULL;
清单＆LT;＆的NameValuePair GT; namevaluepairs中=新的ArrayList＆LT;＆的NameValuePair GT;（）;
ListView的list1的;@覆盖
公共无效的onCreate（捆绑savedInstanceState）
{
super.onCreate（savedInstanceState）;
的setContentView（R.layout.main）;
list1的=（的ListView）findViewById（android.R.id.list）; // HTTP POST
尝试{
HttpClient的HttpClient的=新DefaultHttpClient（）;
HttpPost httppost =新HttpPost（http://10.0.2.2/food.php）;
HTT presponse响应= httpclient.execute（httppost）;
HttpEntity实体= response.getEntity（）;
是= entity.getContent（）;
}赶上（例外五）{
Log.e（log_tag，在HTTP连接错误+ e.toString（））;
} //响应转换为字符串
尝试{
读者的BufferedReader =新的BufferedReader（新的InputStreamReader（是，ISO-8859-1），8）;
SB =新的StringBuilder（）;
sb.append（reader.readLine（）+\\ n）;
串行=0; 而（（行= reader.readLine（））！= NULL）{
sb.append（行+\\ n）;
} is.close（）;
结果= sb.toString（）; }赶上（例外五）{
Log.e（log_tag，错误转换结果+ e.toString（））;
} //配对数据
串fd_id;
串fd_name;
尝试{
JSONArray jArray =新JSONArray（结果）;
JSONObject的json_data = NULL; 的for（int i = 0; I＆LT; jArray.length（）;我++）{
json_data = jArray.getJSONObject（ⅰ）;
fd_id = json_data.getString（FOOD_ID）; fd_name = json_data.getString（FOOD_NAME）;
nameValuePairs.add（新名单＆LT;字符串，字符串＆GT;（fd_id，fd_name））;
} list1.setAdapter（新ArrayAdapter<NameValuePair>(getApplicationContext(),android.R.layout.simple_expandable_list_item_1,nameValuePairs)); }赶上（JSONException E1）{
Toast.makeText（getBaseContext（），无食物中，Toast.LENGTH_LONG）.show（）;
}赶上（ParseException的E1）{
e1.printStackTrace（）;
}}
}
list.java
包com.Valluru;
进口org.apache.http.NameValuePair;进口android.R.integer;公共类列表＆LT; T，V＆GT;实现的NameValuePair {
数据T;
V文本;公示名单（T数据，V文本）
{
this.data =数据;
this.text =文本;
}@覆盖
公共字符串的toString（）{
返回text.toString（）;
}@覆盖
公共字符串的getName（）{
返回（字符串）数据;
}@覆盖
公共字符串的getValue（）{
返回（字符串）文本;
}
}
food.php
＆LT; PHP
mysql_connect（localhost的根）;
mysql_select_db（食物）;
$ SQL =的mysql_query（SELECT * FROM食物放在FOOD_NAME LIKE'％'）;
而（$行= mysql_fetch_assoc（$ SQL））$输出[] = $行;
打印（json_en code（$输出））;
mysql_close（）;
？＆GT;
I am totally green in android. And I want to create App that gets data from server and shows it in the app. Can anyone tell me how to start it? I tried this code below. But only exception is showing that food isn't found.
private EditText outputStream;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
String result = null;
InputStream input = null;
StringBuilder sbuilder = null;
outputStream = (EditText)findViewById(R.id.output);
ArrayList <NameValuePair> nameValuePairs = new ArrayList <NameValuePair>();
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("ik.su.lt/~jbarzelis/index.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
if (response.getStatusLine().getStatusCode() != 200) {
Log.d("MyApp", "Server encountered an error");
}
HttpEntity entity = response.getEntity();
input = entity.getContent();
}
catch(Exception e){
e.printStackTrace();
}
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(input,"iso-8859-1"),8);
sbuilder = new StringBuilder();
String line = null;
while((line = reader.readLine()) != null){
sbuilder.append(line + "\n");
}
input.close();
result = sbuilder.toString();
}
catch(Exception e){
e.printStackTrace();
}
int fd_id;
String fd_name;
try{
JSONArray jArray = new JSONArray(result);
JSONObject json_data = null;
for(int i=0;i<jArray.length();i++){
json_data = jArray.getJSONObject(i);
fd_id = json_data.getInt("FOOD_ID");
fd_name = json_data.getString("FOOD_NAME");
outputStream.append(fd_id +" " + fd_name + "\n");
}
}
catch(JSONException e1){
Toast.makeText(getBaseContext(), "No food found", Toast.LENGTH_LONG).show();
}
catch(ParseException e1){
e1.printStackTrace();
}
}
PHP code is correct it shows data. I think somethig is wrong with the code above.
<?php
mysql_connect("localhost","********","**********");
mysql_select_db("test");
$sql = mysql_query("select FOOD_NAME as 'Maistas' from FOOD where FOOD_NAME like 'A%'");
while($row = mysql_fetch_assoc($sql)) $output[]=$row;
print(json_encode($output));
mysql_close;
?>
解决方案
package com.Valluru;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.List;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.ListActivity;
import android.content.Intent;
import android.net.ParseException;
import android.net.Uri;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.ArrayAdapter;
import android.widget.ListView;
import android.widget.TextView;
import android.widget.Toast;
public class Food extends ListActivity {
String result = null;
InputStream is = null;
StringBuilder sb=null;
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
ListView list1;
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
list1 = (ListView) findViewById(android.R.id.list);
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://10.0.2.2/food.php");
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag", "Error in http connection"+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
sb = new StringBuilder();
sb.append(reader.readLine() + "\n");
String line="0";
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
//paring data
String fd_id;
String fd_name;
try{
JSONArray jArray = new JSONArray(result);
JSONObject json_data=null;
for(int i=0;i<jArray.length();i++){
json_data = jArray.getJSONObject(i);
fd_id =json_data.getString("FOOD_ID");
fd_name = json_data.getString("FOOD_NAME");
nameValuePairs.add(new list<String, String>(fd_id, fd_name));
}
list1.setAdapter(new ArrayAdapter<NameValuePair>(getApplicationContext(),android.R.layout.simple_expandable_list_item_1,nameValuePairs));
}catch(JSONException e1){
Toast.makeText(getBaseContext(), "No FOOD Found", Toast.LENGTH_LONG).show();
}catch (ParseException e1){
e1.printStackTrace();
}
}
}
list.java package com.Valluru;
import org.apache.http.NameValuePair;
import android.R.integer;
public class list<T,V> implements NameValuePair {
T data;
V text;
public list(T data, V text)
{
this.data = data;
this.text = text;
}
@Override
public String toString(){
return text.toString();
}
@Override
public String getName() {
return (String) data;
}
@Override
public String getValue() {
return (String) text;
}
}
food.php
<?php
mysql_connect("localhost","root");
mysql_select_db("FOOD");
$sql=mysql_query("select * from FOOD where FOOD_NAME like '%'");
while($row=mysql_fetch_assoc($sql)) $output[]=$row;
print(json_encode($output));
mysql_close();
?>
这篇关于机器人，正从服务器的数据的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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