上传视频从机器人到服务器？ [英] Upload Video from android to server?

问题描述

中的任何一个提出了一些样本上传的视频从SD卡到远程服务器。

Any one suggest some sample to upload an video to from sdcard to remote server.

在此先感谢。

推荐答案

前段时间有同样的问题。这里有一个code。

Had the same issue some time ago. Here's a code.

public static int upLoad2Server(String sourceFileUri) {
  String upLoadServerUri = "your remote server link";
  // String [] string = sourceFileUri;
  String fileName = sourceFileUri;

  HttpURLConnection conn = null;
  DataOutputStream dos = null;
  DataInputStream inStream = null;
  String lineEnd = "\r\n";
  String twoHyphens = "--";
  String boundary = "*****";
  int bytesRead, bytesAvailable, bufferSize;
  byte[] buffer;
  int maxBufferSize = 1 * 1024 * 1024;
  String responseFromServer = "";

  File sourceFile = new File(sourceFileUri);
  if (!sourceFile.isFile()) {
   Log.e("Huzza", "Source File Does not exist");
   return 0;
  }
  try { // open a URL connection to the Servlet
   FileInputStream fileInputStream = new FileInputStream(sourceFile);
   URL url = new URL(upLoadServerUri);
   conn = (HttpURLConnection) url.openConnection(); // Open a HTTP  connection to  the URL
   conn.setDoInput(true); // Allow Inputs
   conn.setDoOutput(true); // Allow Outputs
   conn.setUseCaches(false); // Don't use a Cached Copy
   conn.setRequestMethod("POST");
   conn.setRequestProperty("Connection", "Keep-Alive");
   conn.setRequestProperty("ENCTYPE", "multipart/form-data");
   conn.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary);
   conn.setRequestProperty("uploaded_file", fileName);
   dos = new DataOutputStream(conn.getOutputStream());

   dos.writeBytes(twoHyphens + boundary + lineEnd);
   dos.writeBytes("Content-Disposition: form-data; name=\"uploaded_file\";filename=\""+ fileName + "\"" + lineEnd);
   dos.writeBytes(lineEnd);

   bytesAvailable = fileInputStream.available(); // create a buffer of  maximum size
   Log.i("Huzza", "Initial .available : " + bytesAvailable);

   bufferSize = Math.min(bytesAvailable, maxBufferSize);
   buffer = new byte[bufferSize];

   // read file and write it into form...
   bytesRead = fileInputStream.read(buffer, 0, bufferSize);

   while (bytesRead > 0) {
    dos.write(buffer, 0, bufferSize);
     bytesAvailable = fileInputStream.available();
     bufferSize = Math.min(bytesAvailable, maxBufferSize);
    bytesRead = fileInputStream.read(buffer, 0, bufferSize);
    }

   // send multipart form data necesssary after file data...
   dos.writeBytes(lineEnd);
   dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

   // Responses from the server (code and message)
   serverResponseCode = conn.getResponseCode();
   String serverResponseMessage = conn.getResponseMessage();

   Log.i("Upload file to server", "HTTP Response is : " + serverResponseMessage + ": " + serverResponseCode);
   // close streams
   Log.i("Upload file to server", fileName + " File is written");
   fileInputStream.close();
   dos.flush();
   dos.close();
  } catch (MalformedURLException ex) {
   ex.printStackTrace();
   Log.e("Upload file to server", "error: " + ex.getMessage(), ex);
  } catch (Exception e) {
   e.printStackTrace();
  }
//this block will give the response of upload link
  try {
   BufferedReader rd = new BufferedReader(new InputStreamReader(conn
     .getInputStream()));
   String line;
   while ((line = rd.readLine()) != null) {
    Log.i("Huzza", "RES Message: " + line);
   }
   rd.close();
  } catch (IOException ioex) {
   Log.e("Huzza", "error: " + ioex.getMessage(), ioex);
  }
  return serverResponseCode;  // like 200 (Ok)

 } // end upLoad2Server

2）

int reponse=upLoad2Server(""+filepath);

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