OpenGL的着色器。通过浮动的数组 [英] OpenGL Shaders. Pass array of float

问题描述

在我的场景我有我想要在同一时间，但是，不同的角度旋转许多对象。

On my scene i have many objects that i want to rotate at the same time but on different angles.

我有一个计算每个物体的位置和绘制整个场景的着色器（通过顶点数组与顶点数组的着色器）。

I have a shader that computes position of each object and draw the whole scene (pass vertex array into the shader with array of vertexes).

    "uniform float uRotation;" +
    ...
    "   mat4 mz = mat4(1.0);" +
    "   mz[0][0] = cos(rotation);" +
    "   mz[0][1] = sin(rotation);" +
    "   mz[1][0] = -sin(rotation);" +
    "   mz[1][1] = cos(rotation);" +
    ...
    gl_Position = uMVPMatrix * (aPosition *mz);

我有我所有的顶点，索引，颜色等在阵列（而不是1阵列的每个对象，但1阵列顶点，一个颜色等偏移量）。

i have all my vertexes, indexes, colors etc in arrays (not 1 array for each object, but 1 array with offset for vertexes, one for colors etc.).

我想通过float型数组（角度为每一个对象）在一个浮动[]，但没有什么是happinig。

I want to pass array of floats (angles for each "object") in one float[], but nothing is happinig.

    public void setRotations(float[] rotations)
    {
        GLES20.glUniform3fv(muRotation, rotations.length, rotations, 0);    
    }

如果通过，只用一个浮点数一切正常。

if pass and use only one float everything is ok.

我如何可以通过特定的浮动对每个对象（例如我想提请20的矩形（我有一个vetrex数组：漂浮[20 * 3 * 4），因为我知道我必须有浮每个顶点：旋转：漂浮[20 * 4]）？

How can i pass specific float for each object (for example i want to draw 20 rectangles (i have a vetrex array: float[20*3*4]) as i understand i must have float for each vertex: rotations: float[20*4])?

更新：

我尝试通过阵列作为纹理。

I try to pass array as a texture.

在我的场景中创建资源 - 我尝试创建我的数组（称为面罩）：

When i create resources for the scene - i try to create my array (called mask):

    mask = new float[512*512*4];
    for (int i = 0; i < mask.length; i++)
    {
        mask[i] = 2f;
    }

    GLES20.glActiveTexture(GLES20.GL_TEXTURE1);
    GLES20.glBindTexture(GLES20.GL_TEXTURE_2D, 1029384756);
    GLES20.glTexImage2D(GLES20.GL_TEXTURE_2D, 1, GLES20.GL_RGBA, 512, 512, 0, GLES20.GL_RGBA, GLES20.GL_FLOAT, FloatBuffer.wrap(mask));
    GLES20.glTexParameterf(GLES20.GL_TEXTURE_2D, GLES20.GL_TEXTURE_MIN_FILTER, GLES20.GL_LINEAR);
    GLES20.glActiveTexture(GLES20.GL_TEXTURE0);

然后当我在现场绘制新的项目我使用着色器，并试图通过我的数组：

Then when i draw new item on scene i use shader and try to pass my array:

    setShaderProgram(ShaderProgram.getInstance());

    GLES20.glActiveTexture(GLES20.GL_TEXTURE1);
    GLES20.glUniform1i(ShaderProgram.sUniformMask, GLES20.GL_TEXTURE1);
    GLES20.glBindTexture(GLES20.GL_TEXTURE_2D, 1029384756);
    GLES20.glActiveTexture(GLES20.GL_TEXTURE0);

但是，当我试图从阵列检查任何价值，如果它> 0.5计算每次给我的假

更新时间：

片段着色器包括：

"uniform sampler2D " + ShaderProgramConstants.UNIFORM_TEXTURE_0 + ";\n" +
"uniform sampler2D " + ShaderProgramConstants.UNIFORM_TEXTURE_1 + ";\n" +
"varying mediump vec2 " + ShaderProgramConstants.VARYING_TEXTURECOORDINATES + ";\n" +

"void main() {\n" +
"vec4 color = texture2D(" + ShaderProgramConstants.UNIFORM_TEXTURE_0 + ", " + ShaderProgramConstants.VARYING_TEXTURECOORDINATES + ");\n" +
"vec4 mask = texture2D(" + ShaderProgramConstants.UNIFORM_TEXTURE_1 + ", " + ShaderProgramConstants.VARYING_TEXTURECOORDINATES + ");\n" +
"float maskVal = mask.r;\n" ...

色和掩模纹理具有相同的尺寸

color and mask textures have the same dimensions

推荐答案

GLES20.glUniform1i（ShaderProgram.sUniformMask，GLES20.GL_TEXTURE1）;

如果这是你的采样均匀，应改为：

If this is your sampler uniform, it should read:

GLES20.glUniform1i（ShaderProgram.sUniformMask，1）; （不GL_TEXTURE1）

GLES20.glUniform1i(ShaderProgram.sUniformMask, 1); (not GL_TEXTURE1)

有关sampler0类似：

Similar for sampler0:

GLES20.glUniform1i（ShaderProgram.sUniformMask，0）;

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