如何将二进制表示形式的字节转储为十进制字符串? [英] how to dump a binary representation bytes to decimal string?

问题描述

下面是十六进制转储函数，但我需要的是dec dump.

Below is the hex dump function, but what I need is dec dump.

void DumpBytes(unsigned char* inputBytes,int inputBytesLength,char* ouputString)
{
    unsigned char const Hex[] = "01234567890abcdef";
    for (int i = 0; i < inputBytesLength; i++)
    {
        unsigned char binByte = inputBytes[i];
        ouputString[2*i] = (Hex[(binByte & 0xf0) >> 4]);
        ouputString[2*i + 1] = (Hex[binByte & 0x0f]);
    }
}

如何将字节转储为十进制字符串而不是十六进制字符串?

How do I dump bytes to decimal string instead of heximal string?

Thanks in advance!

推荐答案

这很简单:使用sprintf和strcat函数.

It''s quite trivial: use the sprintf and strcat functions.

void DumpBytes(unsigned char* inputBytes, int inputBytesLength, char* ouputString)
{
   char tmp[5]; // 0-255 + whitespace + terminating NULL -> max 5 char

   outputString[0] = '\0';
   for(int i = 0; i < inputBytesLength; i++)
   {
      sprintf_s(tmp, "%u ", inputBytes[i]);
      strcat(outputString, tmp);
   }
}

一个C ++答案，更安全地解决潜在的输出大小问题:

A C++ answer, safer on output size potential problem:

#include <sstream>
#include <iterator>
std::string DumpBytes(unsigned char* inputBytes, int inputBytesLength)
{
   std::ostringstream oss;
   std::copy_n(inputBytes, inputBytesLength, std::ostream_iterator<int>(oss, " "));
   return oss.str();
}

欢呼声，
AR

cheers,
AR

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