Golang：如何将字符串转换为二进制表示 [英] Golang: How to convert String to binary representation

问题描述

在golang中，如何将字符串转换为二进制字符串？
示例：'CC'变为10000111000011

解决方案

这是一个简单的方法：

  func stringToBin（s string）（binString string）{
 for _，c：= range s {
 binString = fmt .Sprintf（％s％b，binString，c）
} 
返回
} 
  

正如我在另一个答案的评论中所述，您还可以使用变体％s％.8b，它将填充字符串零，如果你需要或想要表示8位......然而，如果你的角色需要大于8位来表示，例如希腊字符，这不会有什么区别：

Φ1110100110

<11> 1110111011

<11> 1111111100

或者这些数学符号打印14位：

≠10001001100000

⊂10001010000010

⋅10001011000101

所以要注意的是：这里的例子是一个简单的演示，它满足原始文章中的条件，而不是用于处理Unicode代码点的base2表示的强大工具。

In golang, how can I convert a string to binary string? Example: 'CC' becomes 10000111000011

解决方案

This is a simple way to do it:

func stringToBin(s string) (binString string) {
    for _, c := range s {
        binString = fmt.Sprintf("%s%b",binString, c)
    }
    return 
}

As I included in a comment to another answer you can also use the variant "%s%.8b" which will pad the string with leading zeros if you need or want to represent 8 bits... this will however not make any difference if your character requires greater than 8 bit to represent, such as Greek characters:

Φ 1110100110

λ 1110111011

μ 1110111100

Or these mathematical symbols print 14 bits:

≠ 10001001100000

⊂ 10001010000010

⋅ 10001011000101

So caveat emptor: the example herein is meant as a simple demonstration that fulfills the criteria in the original post, not a robust means for working with base2 representations of Unicode codepoints.

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