将C字符串转换为二进制表示形式 [英] Converting C string to binary representation

问题描述

在ANSI C中，如何将字符串转换为二进制字节数组? 所有的谷歌搜索和搜索都为我提供了C ++和其他(而不是C)的答案.

In ANSI C, how do we convert a string in to an array of binary bytes? All the googling and searching gives me answers for C++ and others and not C.

我的一个想法是将字符串转换为ASCII，然后将每个ASCII值转换为其二进制. (Du！)我知道这是最愚蠢的想法，但是我不确定其他任何选择.

One idea I had was to convert the string into ASCII and then convert each ASCII value into its binary. (Duh!) I know it is the dumbest of ideas but I am not sure of any other option.

我听说过Java中的编码功能.我不确定这是否适合相同的目的，并且可以被C采纳.

I've heard abt the encoding function in Java. I am not sure if that suits the same purpose and can be adopted to C.

string = "Hello"
bytearr[] = 10100101... some byte array..

如果有人可以对此有所启发，那就太好了.

It would be great if someone can throw some light on this.

谢谢！

推荐答案

还是您的意思是如何将C字符串转换为二进制表示形式?

Or did you mean how to convert C string to binary representation?

这里是一种可以将字符串转换为二进制表示的解决方案.可以很容易地对其进行更改，以将二进制字符串保存到字符串数组中.

Here is one solution which can convert strings to binary representation. It can be easily altered to save the binary strings into array of strings.

#include <stdio.h>

int main(int argc, char *argv[])
{
    if(argv[1] == NULL) return 0; /* no input string */

    char *ptr = argv[1];
    int i;

    for(; *ptr != 0; ++ptr)
    {
        printf("%c => ", *ptr);

        /* perform bitwise AND for every bit of the character */
        for(i = 7; i >= 0; --i) 
            (*ptr & 1 << i) ? putchar('1') : putchar('0');

        putchar('\n');
    }

    return 0;
}

示例输入&输出:

Example input & output:

./ascii2bin hello

h => 01101000
e => 01100101
l => 01101100
l => 01101100
o => 01101111

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