如何计算圆垂直线相交 [英] How to calculate Circle Vertical Line intersect

问题描述

我有以下公式来查找直线和圆的相交点

x = {-B + sqrt [(((B ^ 2)-4AC)]}/2A

其中B = 2mc
A = 1 + m ^ 2
C = c ^ 2-r ^ 2

m表示倾斜
c表示线公式的常量

在找到x之后，我通过将x放入(y = mx + c)找到y的值
但是当坡度为无限(等于垂直线)时我们要做的事情
?

I have following formulas to find intersect points of Line and Circle

x = {-B + sqrt[((B^2) - 4AC)]} / 2A

where B = 2mc
A = 1 + m^2
C = c^2 - r^2

m means slop
c means Constant of line formula

after finding x I find value of y by putting x in (y = mx + c)
but what we have to do when slop is infinite (means vertical line)
?

推荐答案

一条垂直线作为等式

A vertical line as equation

x = K

其中K是常量.
因此，您必须求解y的原始方程式，即:

where K is a const.
Hence, you''ve to solve the original equation for y, namely:

(K-a)^2 + (y-b)^2 = r^2

也就是说，这只是一个二次方程.
:)

That is, again, just a quadratic equation.
:)

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