在C ++编码井字游戏中需要帮助 [英] Need help in c++ coding tictac toe game

问题描述

#include <iostream>
#include <cstdlib>
#include <conio.h>
#include "GUI.cpp"
using namespace std;

void display( char board[3][3][3][3] )
{
    for( int R=0; R<3; R++ )
    {
        for( int r=0; r<3; r++ )
        {
            for( int C=0; C<3; C++ )
            {
                for( int c=0; c<3; c++ )
                {
                    setColor(RGBI(1,0,0,1),RGBI(1,1,0,1));
                    cout << board[R][C][r][c];
                    setColor(RGBI(1,1,1,0),RGBI(0,0,0,0));
                }
                cout <<" ";
            }
            cout << endl;
        }
        cout << endl;
    }
    setColor(RGBI(1,1,1,0),RGBI(0,0,0,0));
    cout <<"Click on ";
    setColor(RGBI(1,0,0,1),RGBI(1,1,0,1));
    cout <<"highlighted cell";
    setColor(RGBI(1,1,1,0),RGBI(0,0,0,0));
    cout <<" above using the [Mouse]"<< endl;
}

bool mouseToBoardCoord( MouseClick const& m, int& R, int& C, int& r, int& c )
{
    // Player clicked on first big row?
    if( (0 <= m.x) && (m.x < 3) && (0 <= m.y) && (m.y < 3) )
    {
        R = 0;
        C = 0;

        if     ( m.x == 0 )c = 0;
        else if( m.x == 1 )c = 1;
        else if( m.x == 2 )c = 2;

        if     ( m.y == 0 )r = 0;
        else if( m.y == 1 )r = 1;
        else if( m.y == 2 )r = 2;
    }
    else if( (4 <= m.x) && (m.x < 7) && (0 <= m.y) && (m.y < 3) )
    {
        R = 0;
        C = 1;

        if     ( m.x == 4 )c = 0;
        else if( m.x == 5 )c = 1;
        else if( m.x == 6 )c = 2;

        if     ( m.y == 0 )r = 0;
        else if( m.y == 1 )r = 1;
        else if( m.y == 2 )r = 2;
    }
    else if( (8 <= m.x) && (m.x < 11) && (0 <= m.y) && (m.y < 3) )
    {
        R = 0;
        C = 2;

        if     ( m.x == 8  )c = 0;
        else if( m.x == 9  )c = 1;
        else if( m.x == 10 )c = 2;

        if     ( m.y == 0  )r = 0;
        else if( m.y == 1  )r = 1;
        else if( m.y == 2  )r = 2;
    }

    // Player clicked on second big row?
    else if( (0 <= m.x) && (m.x < 3) && (4 <= m.y) && (m.y < 7) )
    {
        R = 1;
        C = 0;

        if     ( m.x == 0 )c = 0;
        else if( m.x == 1 )c = 1;
        else if( m.x == 2 )c = 2;

        if     ( m.y == 4 )r = 0;
        else if( m.y == 5 )r = 1;
        else if( m.y == 6 )r = 2;
    }
    else if( (4 <= m.x) && (m.x < 7) && (4 <= m.y) && (m.y < 7) )
    {
        R = 1;
        C = 1;

        if     ( m.x == 4 )c = 0;
        else if( m.x == 5 )c = 1;
        else if( m.x == 6 )c = 2;

        if     ( m.y == 4 )r = 0;
        else if( m.y == 5 )r = 1;
        else if( m.y == 6 )r = 2;
    }
    else if( (8 <= m.x) && (m.x < 11) && (4 <= m.y) && (m.y < 7) )
    {
        R = 1;
        C = 2;

        if     ( m.x == 8  )c = 0;
        else if( m.x == 9  )c = 1;
        else if( m.x == 10 )c = 2;

        if     ( m.y == 4  )r = 0;
        else if( m.y == 5  )r = 1;
        else if( m.y == 6  )r = 2;
    }

    // Player clicked on third big row?
    else if( (0 <= m.x) && (m.x < 3) && (8 <= m.y) && (m.y < 11) )
    {
        R = 2;
        C = 0;

        if     ( m.x == 0  )c = 0;
        else if( m.x == 1  )c = 1;
        else if( m.x == 2  )c = 2;

        if     ( m.y == 8  )r = 0;
        else if( m.y == 9  )r = 1;
        else if( m.y == 10 )r = 2;
    }
    else if( (4 <= m.x) && (m.x < 7) && (8 <= m.y) && (m.y < 11) )
    {
        R = 2;
        C = 1;

        if     ( m.x == 4  )c = 0;
        else if( m.x == 5  )c = 1;
        else if( m.x == 6  )c = 2;

        if     ( m.y == 8  )r = 0;
        else if( m.y == 9  )r = 1;
        else if( m.y == 10 )r = 2;
    }
    else if( (8 <= m.x) && (m.x < 11) && (8 <= m.y) && (m.y < 11) )
    {
        R = 2;
        C = 2;

        if     ( m.x == 8  )c = 0;
        else if( m.x == 9  )c = 1;
        else if( m.x == 10 )c = 2;

        if     ( m.y == 8  )r = 0;
        else if( m.y == 9  )r = 1;
        else if( m.y == 10 )r = 2;
    }

    // Player clicked outside our 9x9 board?
    else
    {
        return false;
    }

    // Player clicked inside our 9x9 board
    return true;
}

int main()
{
    char board[3][3][3][3] = {};
    bool FirstTime = true;
    int prev_r;
    int prev_c;

    while(true)
    {
        system("CLS");
        display(board);

        MouseClick m = getMouseClick();
        int                     R,C,r,c;
        if( mouseToBoardCoord(m,R,C,r,c) )
        {
//
// neeed help in this section
//
           if (FirstTime)
            {
                 board[R][C][r][c] = 'X';
                 FirstTime = false;
                 prev_r = r;
                 prev_c = c;
            }
            else
            {
             if ( R == prev_r && C == prev_c)
             {
                 board[R][C][r][c] = 'o';
                 prev_r = r;
                 prev_c = c;// need help at here!! 
             }


              }
             }
            }


        }

我不知道如何为替代X和O以及胜利/失败/平局
编码 希望尽快得到您的答复，并对此做一些解释.真的非常感谢

i dont knw how to code for the alternative X and O and for the win / lose/ tie
hope to get ur answer as soon as possible and some explanation on it. really very appreciate

推荐答案

在这样的游戏中，如果计算两个用户的动作，那么(假设我们从1开始)

• 如果count为奇数，则当前移动为''X''一个.

In such a game, if count the moves of both users then (suppose we start with 1)

• if count is odd then the current move is an ''X'' one.

• 如果count是偶数，则当前移动是''O''一个.

• if count is even then the current move is an ''O'' one.

这篇关于在C ++编码井字游戏中需要帮助的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！