带有特殊字符的Json_decode [英] Json_decode with special chars

问题描述

我遇到了一个很大的问题，即通过jQuery Ajax将数据作为JSON发布到我的服务器. JSLint表示数据正常，并且请求的Content-Type设置为application/x-www-form-urlencoded; charset=UTF-8.服务器在PHP 5.2.11上运行，所以我不能使用json_last_error().

I got a big problem posting data via jQuery Ajax as JSON to my Server. JSLint say the data is OK and the Content-Type of the request is set to application/x-www-form-urlencoded; charset=UTF-8. Server runs on PHP 5.2.11 so I can't use json_last_error().

我尝试了url_decode，utf8_decode和html_entities_decode，但似乎无济于事.

I tried url_decode, utf8_decode and html_entities_decode, but nothing seems to work.

var_dump(json_decode($jdata));返回null，但是如果我执行var_dump($jdata)，则一切正常. $jdata是发布数据:$jdata = $this->input->post('requestdata');.

var_dump(json_decode($jdata)); returns null, but if I do a var_dump($jdata) everything looks OK. $jdata is the post data:$jdata = $this->input->post('requestdata');.

以下是从Firebug获取数据的示例示例:

Here some example post data grab from Firebug:

{
    "projectnumber": "345",
    "projecdescription": "345",
    "articles": [
        {
            "position": 1,
            "article_id": 677,
            "online_text": "3 Behälter; Band I-III nach indiv. Stückliste, Sprache: DE - Sprache: de"
        },
        {
            "position": 2,
            "article_id": 678,
            "online_text": "2 Behälter; Band I-III nach indiv. Stückliste, Sprache: ### - Sprache: en"
        }
    ]
}

我现在尝试了这个:

$string = $this->input->post('requestdata');
var_dump($string);
$json = preg_replace('/,\s*([\]}])/m', '$1', utf8_encode($string));
$json = json_decode($json);
var_dump($json);

结果是:

string(338)"{" projectnumber:" 4444，" projecdescription:" 4444，" articles:[{" position:1，" article_id:676，" online_text:" ## #Behälter; I-III乐队nach个人. Stückliste，Sprache:德国 -语言:de}，{" position:2，" article_id:681，" online_text:" ###Behälter; I-III乐队nach个人. Stückliste，Sprache:### -语音:en}]}" NULL

string(338) "{"projectnumber": "4444", "projecdescription": "4444", "articles": [{"position":1, "article_id": 676, "online_text": "### Behälter; Band I-III nach indiv. Stückliste, Sprache: DE - Sprache: de"}, {"position":2, "article_id": 681, "online_text": "### Behälter; Band I-III nach indiv. Stückliste, Sprache: ### - Sprache: en"}]}" NULL

通过直接将JSON字符串粘贴到PHP源代码中，它可以工作，但不能从帖子中获取它！

By pasting the JSON string direct into the PHP source it works, but getting it from post not!

推荐答案

由于字符串中的新行而出现错误

You are having error because of new line in your string

$string = '{"projectnumber" : "4444","projecdescription" : "4444", "articles" : [{"position":1, "article_id" : 676, "online_text" : "### Behälter; Band I-III nach indiv. Stückliste, Sprache: DE 
 - Sprache: de"},{"position":2, "article_id" : 681, "online_text" : "### Behälter; Band I-III nach indiv. Stückliste, Sprache: ### 
 - Sprache: en"}]}';


$string = preg_replace("/[\r\n]+/", " ", $string);
$json = utf8_encode($string);
$json = json_decode($json);
var_dump($json);

输出

object(stdClass)[1]
  public 'projectnumber' => string '4444' (length=4)
  public 'projecdescription' => string '4444' (length=4)
  public 'articles' => 
    array
      0 => 
        object(stdClass)[2]
          public 'position' => int 1
          public 'article_id' => int 676
          public 'online_text' => string '### Behälter; Band I-III nach indiv. Stückliste, Sprache: DE   - Sprache: de' (length=78)
      1 => 
        object(stdClass)[3]
          public 'position' => int 2
          public 'article_id' => int 681
          public 'online_text' => string '### Behälter; Band I-III nach indiv. Stückliste, Sprache: ###   - Sprache: en' (length=79)

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