如何在JsonConvert.DeserializeObject中处理null/empty值 [英] How to handle null/empty values in JsonConvert.DeserializeObject

问题描述

我有以下代码:

return (DataTable)JsonConvert.DeserializeObject(_data, (typeof(DataTable)));

然后，我尝试了:

var jsonSettings = new JsonSerializerSettings
{
    NullValueHandling = NullValueHandling.Ignore
};

return (DataTable)JsonConvert.DeserializeObject<DataTable>(_data, jsonSettings);

返回行抛出错误:

{将值\"\"转换为键入'System.Double'时出错.}

许多在线解决方案建议使用可空类型创建自定义Class，但这对我不起作用.我不能指望json是某种格式.我无法控制列数，列类型或列名.

Lots of solutions online suggesting creating custom Class with nullable types but this won't work for me. I can't expect the json to be in a certain format. I have no control over the column count, column type, or column names.

推荐答案

您可以为JsonConvert.DeserializeObject提供设置，以告诉它如何处理空值(在这种情况下，还有更多):

You can supply settings to JsonConvert.DeserializeObject to tell it how to handle null values, in this case, and much more:

var settings = new JsonSerializerSettings
                    {
                        NullValueHandling = NullValueHandling.Ignore,
                        MissingMemberHandling = MissingMemberHandling.Ignore
                    };
var jsonModel = JsonConvert.DeserializeObject<Customer>(jsonString, settings);

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