在嵌套对象上使用 JsonConvert.DeserializeObject [英] Using JsonConvert.DeserializeObject on Nested Object

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本文介绍了在嵌套对象上使用 JsonConvert.DeserializeObject的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想在我的应用程序加载时使用 JSON.Net 来处理配置文件的解析.将所有 KVP 保持在同一范围内绝对没问题.但是,我想将其分解为子类别,例如 Settings.WebServer、Settings.GameServer 等.

I want to use JSON.Net to handle parsing a configuration file when my application is loaded. Keeping all KVP's in the same scope works absolutely fine. I would however like to break it down into sub-categories such as Settings.WebServer, Settings.GameServer, etc.

为了便于阅读,我希望能够以这种方式引用各种设置,例如 Settings.WebServer.hostname.目前试图将 WebServer/GameServer 考虑在内的因素正在抛弃这一点.任何人都可以帮助我们做些什么来使其正常工作?

I would like to be able to reference various settings in that manner for readability sake, such as Settings.WebServer.hostname. Currently trying to factor in WebServer/GameServer is throwing this off. Can anyone help with what can be done to get this working?

JSON

{
    "webserver":
    {
        "hostname": "localhost",
        "port": "8888"
    },
    "gameserver":
    {
        "hostname": "123.123.123.123",
        "port": "27015",
        "password": "as@c!qi$"
    }
}

C# 主程序

Settings settings = JsonConvert.DeserializeObject<Settings>(File.ReadAllText(@".\Configs\settings.cfg"));

C# 设置类

namespace SourceMonitor
{
    public class Settings
    {
        public class Webserver
        {
            [JsonProperty("hostname")]
            public string hostname { get; set; }

            [JsonProperty("port")]
            public string port { get; set; }
        }

        public class Gameserver
        {
            [JsonProperty("hostname")]
            public string hostname { get; set; }

            [JsonProperty("port")]
            public string port { get; set; }

            [JsonProperty("password")]
            public string password { get; set; }
        }

        public class RootObject
        {
            [JsonProperty("webserver")]
            public Webserver webserver { get; set; }

            [JsonProperty("gameserver")]
            public Gameserver gameserver { get; set; }
        }
    }
}

推荐答案

您正在尝试序列化/反序列化没有任何属性的 Settings 类,对于您创建的结构,您必须序列化/反序列化 RootObject 类.

You are trying to serialize/deserialize the Settings class which does not have any property, for the structure you created you must serialize/deserialize the class RootObject.

>

如果您想使用 Settings 类,请将其更改为:

If you want to use the Settings class change it to this:

    namespace SourceMonitor
    {
        public class Settings
        {
            public class Webserver
            {
                [JsonProperty("hostname")]
                public string hostname { get; set; }

                [JsonProperty("port")]
                public string port { get; set; }
            }

            public class Gameserver
            {
                [JsonProperty("hostname")]
                public string hostname { get; set; }

                [JsonProperty("port")]
                public string port { get; set; }

                [JsonProperty("password")]
                public string password { get; set; }
            }

            [JsonProperty("webserver")]
            public Webserver webserver { get; set; }

            [JsonProperty("gameserver")]
            public Gameserver gameserver { get; set; }

        }
    }

这篇关于在嵌套对象上使用 JsonConvert.DeserializeObject的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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