Newtonsoft JsonConvert.DeserializeObject如何忽略空对象 [英] Newtonsoft JsonConvert.DeserializeObject how to ignore empty objects

查看:728
本文介绍了Newtonsoft JsonConvert.DeserializeObject如何忽略空对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有以下类定义:

public class Tag
{
    public Guid? TagId { get; set; }
    public string TagText { get; set; }
    public DateTime CreatedOn { get; set; }
}

public class Wiki
{
    public Guid? WikiId { get; set; }
    public string WikiText { get; set; }
    public string Title { get; set; }
    public DateTime CreatedOn { get; set; }
    public IEnumerable<Tag> Tags { get; set; }
}

从数据库中,我得到以下json对象:

From the database i get the following json Object:

{
    "WikiId": "83981284-0AD3-4420-90AB-15E3BF6BD7B7",
    "WikiText": "Text",
    "Title": "Title",
    "CreatedOn": "2017-08-07T09:16:06.0800000",
    "Tags": [{}] // <-- here i would like to ignore the empty Tag object
}

当我现在做一个JsonConvert.DeserializeObject<Wiki>(json)时,我得到一个Wiki对象,其中包含1个具有TagId: null, TagText: null and CreatedOn: "0001-01-01T00:00:00"

When i do now a JsonConvert.DeserializeObject<Wiki>(json) i get a Wiki object with a list of 1 Tag with the values TagId: null, TagText: null and CreatedOn: "0001-01-01T00:00:00"

是否有一种方法可以在反序列化时忽略空的Tag对象?我已经尝试了几个JsonSerializerSettings,但是没有帮助.

Is there a way to ignore the empty Tag object while deserializing? I have tried several JsonSerializerSettings but nothing helped.

推荐答案

在反序列化过程中,可以使用自定义的JsonConverter忽略空对象.这样的事情可能会起作用:

You could use a custom JsonConverter to ignore the empty objects during deserialization. Something like this could work:

class IgnoreEmptyItemsConverter<T> : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return objectType.IsAssignableFrom(typeof(List<T>));
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        List<T> list = new List<T>();
        JArray array = JArray.Load(reader);
        foreach (JObject obj in array.Children<JObject>())
        {
            if (obj.HasValues)
            {
                list.Add(obj.ToObject<T>(serializer));
            }
        }
        return list;
    }

    public override bool CanWrite
    {
        get { return false; }
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }
}

要使用转换器,只需将[JsonConverter]属性添加到您的Tags属性中,如下所示:

To use the converter, just add a [JsonConverter] attribute to your Tags property like this:

public class Wiki
{
    ...
    [JsonConverter(typeof(IgnoreEmptyItemsConverter<Tag>))]
    public IEnumerable<Tag> Tags { get; set; }
}

提琴: https://dotnetfiddle.net/hrAFsh

这篇关于Newtonsoft JsonConvert.DeserializeObject如何忽略空对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
相关文章
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆